(a) The vertical motion equation for the ball is h = 8 + 48t - 16t².
(b) The time for the ball to hit the ground is 3.15 s.
(c) The time for the ball to travel 56 ft above the ground is 0.79 s.
<h3>Vertical motion equation for the ball</h3>
The vertical motion equation for the ball is calculated as follows;
h = h₀ + vt - ¹/₂gt²
h = 8 + 48t - ¹/₂(32)t²
h = 8 + 48t - 16t²
<h3>Time for the ball to hit the ground</h3>
0 = 8 + 48t - 16t²
solve the above quadratic equation with formula method;
a = -16, b = 48, c = 8
t = 3.15 s
<h3>Time for the ball to be 56 ft above the ground</h3>
- let upward motion be positive
h = 8 + 48t + 16t²
56 = 8 + 48t + 16t²
0 = -48 + 48t + 16t²
solve the above quadratic equation with formula method;
a = 16, b = 48, c = -48
t = 0.79 s
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Answer:
x = 30
Step-by-step explanation:
Put in proportions =
Cross multiply and get 27x = 45 x 18
OR...
27x = 810.
THEN...
divide by 27 on both sides to get 30
x = 30
-3(x - 2) = 2(x - 7) remove the parentheses
-3x + 6 = 2x - 14. Move the terms
-3x - 2x = -14 - 6. Collect like terms. Calculate.
-5x = -20. Divide both sides.
Solution: x = 4
Answer:
y = -2
Step-by-step explanation:
The line x = -3 is a vertical one; the slope of a line perpendicular to x = -3 is zero (0). Recall that the slope of a vertical line is undefined and that of a line perpendicular to a vertical line is 0.
Then, to write the equation of the perpendicular line, we borrow the '-2' from (-9, -2) and write y = -2. This line does indeed pass through (-9, -2) and every other point whose y-component is -2.