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timofeeve [1]
3 years ago
7

4a2b-6ab2 +12ab3 Factorise​

Mathematics
1 answer:
zlopas [31]3 years ago
3 0
38ab you gotta calculate the product which is 8 and 36 then collect like terms and you get 38ab
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What is 3a+2b-5a+b simplified?
marishachu [46]

Answer:

-a + b

Step-by-step explanation:

7 0
3 years ago
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12x^2+20=50 what is x
LenaWriter [7]

Answer: x=1.5811389999999999 , or 1.59

Step-by-step explanation:

First, Subtract 20 from both sides.

      12x2+20−20=50−20

      12x2=30

 Then, Divide both sides by 12:

12x^2/12 = 30/12

⇒ you get : x^2 = 5/2

After, Take square root.

x= ± √ 5/2

Finally you answer is going to be =1.5811389999999999 OR, 1.59

* Hopefully this helps:) Mark me the brainliest:)

<em>∞ 234483279c20∞</em>

7 0
3 years ago
Video Example EXAMPLE 1 Find the linearization of the function f(x) = x + 1 at a = 3 and use it to approximate the numbers 3.98
Blizzard [7]

Answer:

  the linearization is y = 1/4x +5/4

  the linearization will produce <em>overestimates</em>

  the values computed from this linearization are ...

     f(3.98) ≈ 2.245

     f(4.05) ≈ 2.2625

Step-by-step explanation:

Apparently, you have ...

  f(x)=\sqrt{x+1}

from which you have correctly determined that ...

  f'(x)=\dfrac{1}{2\sqrt{x+1}}

so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...

  g(x) = (1/4)(x -3) +2

  g(x) = (1/4)x +5/4

__

The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.

__

At the given values, we find ...

  g(3.98) = 2.245

  g(4.05) = 2.2625

4 0
4 years ago
I need help with both please no links!
nlexa [21]

Answer:

The first one- 24, The second one-B

Step-by-step explanation:

The first one-Top corner=110, 110+46=156, 180-156=24

The other one-I have no clue how to explain it

4 0
3 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
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