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mamaluj [8]
3 years ago
6

Which of the following equations is an example of inverse variation between variables x and y

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

option A y=9/x

Step-by-step explanation:

It is said that two variables x and y vary inversely if the increase of one of the variables causes the other to decrease.

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Find the derivative of
kirill [66]

Answer:

\displaystyle y'(1, \frac{3}{2}) = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \frac{3}{2x^2}<u />

\displaystyle \text{Point} \ (1, \frac{3}{2})

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Rewrite]:                                            \displaystyle y = \frac{3}{2}x^{-2}
  2. Basic Power Rule:                                                                                             \displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}
  3. Simplify:                                                                                                             \displaystyle y' = -3x^{-3}
  4. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = \frac{-3}{x^3}

<u>Step 3: Solve</u>

  1. Substitute in coordinate [Derivative]:                                                              \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}
  2. Evaluate exponents:                                                                                         \displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}
  3. Divide:                                                                                                               \displaystyle y'(1, \frac{3}{2}) = -3

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0
2 years ago
Tanya, Will, and juan are playing a game online.juan scores 101,473 points.tanya scores 9,879 fewer points than juan and will sc
Dimas [21]
You need to take 101473 and subtract 9879 which equals 91593 and then add 9853 to equal 101447
5 0
3 years ago
Read 2 more answers
The water temperature required for a certain manufacturing process is 134°F. However, the process allows for a variation of 7°F
Y_Kistochka [10]

Answer:

The temperature that represents a smaller value would be the one with negative eighty (or -80) degrees Fahrenheit. Although it is negative, the value of 80 does not mean it has a smaller value as to 134 degrees. It is just that the difference between the absolute values of the two show that 134 degrees Fahrenheit has a bigger value.

Step-by-step explanation:

3 0
3 years ago
Solve for x.7x + 14 – 2x = −x + 12 – x − 19A.x = −3B.x = −1C.x = 1D.x = 3
lara31 [8.8K]
7x+14-2x=-x+12-x-19
collect like terms
7x-2x+X+X+19=12-14
7x+19+2
7x=-21
x-21/7
X=-3
4 0
3 years ago
The quotient of 5/31 divided by 15/23, reduced to the lowest fraction, is
Nataliya [291]
If you would like to solve 5/31 / 15/23, you can calculate this using the following steps:

5/31 / 15/23 = 5/31 * 23/15 = 23/93

The correct result would be C. 23/93.
6 0
3 years ago
Read 2 more answers
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