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2 years ago

HELP PLEASE I REALLY NEED THE ANSWERS

Physics

1 answer:

Paul [167]2 years ago

8 0

$\star\:{\underline{\underline{\sf{\purple{ \: Question \: 19\: }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Given \: :}}}}}}$

☆ Number of resistors = 5

☆ Resistance of each resistors = $\tt \dfrac{1}{5} \text{\O}mega$

${\large{\textsf{\textbf{\underline{\underline{To \: Find \: :}}}}}}$

☆ Maximum resistance which can be made.

${\large{\textsf{\textbf{\underline{\underline{Solution \: :}}}}}}$

• To get maximum resistance, connect the all the given resistances in series.

For,

Series combination :- 

$\longrightarrow \sf R_{s} = R_{1} + R_{2} + R_{3} + R_{4} + R_{5}$

$\longrightarrow \sf R_{s}= \dfrac{1}{5} + \dfrac{1}{5} + \dfrac{1}{5} + \dfrac{1}{5} + \dfrac{1}{5}$

$\longrightarrow \sf R_{s} = \dfrac{1 + 1 + 1 + 1 + 1}{5}$

$\longrightarrow \sf R_{s} = \cancel{ \dfrac{5}{5} }$

$\longrightarrow \sf R_{s} = \purple{1 \: \text{\O}mega}$

$\therefore$ Maximum resistance is 1 Ω.

$\star\:{\underline{\underline{\sf{\red{ \: Question \: 20\: }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Given \: :}}}}}}$

☆ Number of resistors = 5

☆ Resistance of each resistors = $\tt \dfrac{1}{5} \text{\O}mega$

${\large{\textsf{\textbf{\underline{\underline{To \: Find \: :}}}}}}$

☆ Minimum resistance which can be made.

${\large{\textsf{\textbf{\underline{\underline{Solution \: :}}}}}}$

• To get minimum resistance, connect the all the given resistances in parallels.

For,

Parallel combination :- 

$\longrightarrow \sf \dfrac{1}{R_{p}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\dfrac{1}{R_4}+\dfrac{1}{R_5}$

$\longrightarrow \sf\dfrac{1}{R_{p}}= \dfrac{1}{ \frac{1}{5} } + \dfrac{1}{ \frac{1}{5} } + \dfrac{1}{ \frac{1}{5} } + \dfrac{1}{ \frac{1}{5} } + \dfrac{1}{ \frac{1}{5} }$

$\longrightarrow \sf\dfrac{1}{R_{p}}= 1 \times \dfrac{5}{1} +1 \times \dfrac{5}{1} +1 \times \dfrac{5}{1} + 1 \times \dfrac{5}{1} + 1 \times \dfrac{5}{1}$

$\longrightarrow \sf\dfrac{1}{R_{p}}= \dfrac{5}{1} + \dfrac{5}{1} + \dfrac{5}{1} + \dfrac{5}{1} + \dfrac{5}{1}$

$\longrightarrow \sf\dfrac{1}{R_{p}}= 25$

$\longrightarrow \sf R_{p}= \red{ \dfrac{1}{25} \: \text{\O}mega}$

$\therefore$ Minimum resistance is $\dfrac{1}{25}$ Ω.

${\large{\textsf{\textbf{\underline{\underline{Note \: :}}}}}}$

☆ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

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A weight lifter applies an upward force of 1100 N while lowering a dumbbell

Paul [167]

Answer:

Explanation:

$work = force \times distance$

$work = 1100 \times 0.5$

$= 550 \: j$

hope it helped a lot

pls mark brainliest with due respect .

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2 years ago

This equation is known as the ideal gas law, and it can be used to predict the behavior of many gases at relatively low pressure

Masja [62]

The correct answer is
C) either the pressure of the gas, the volume of the gas, or both, will increase.

In fact, the ideal gas law can be written as
 $pV=nRT$
where
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n is the number of moles
R is the gas constant
T is the absolute temperature of the gas

We can see that if the temperature T increases, then the term on the right in the equation increases, therefore the term on the left should increase as well. In order for this to be possible, at least one between p and V should increase, or also both of them. Therefore, the correct answer is C.

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3 years ago

A crate rests on a flatbed truck which is initially traveling at 17.9 m/s on a level road. The driver applies the brakes and the

Mamont248 [21]

Answer:

The minimum coefficient of friction required is 0.35.

Explanation:

The minimum coefficient of friction required to keep the crate from sliding can be found as follows:

$-F_{f} + F = 0$

$-F_{f} + ma = 0$

$\mu mg = ma$

$\mu = \frac{a}{g}$

Where:

μ: is the coefficient of friction

m: is the mass of the crate

g: is the gravity

a: is the acceleration of the truck

The acceleration of the truck can be found by using the following equation:

$v_{f}^{2} = v_{0}^{2} + 2ad$

$a = \frac{v_{f}^{2} - v_{0}^{2}}{2d}$

Where:

d: is the distance traveled = 46.1 m

$v_{f}$ : is the final speed of the truck = 0 (it stops)

$v_{0}$ : is the initial speed of the truck = 17.9 m/s

$a = \frac{-(17.9 m/s)^{2}}{2*46.1 m} = -3.48 m/s^{2}$

If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.

$\mu = \frac{a}{g}$

$\mu = \frac{3.48 m/s^{2}}{9.81 m/s^{2}}$

$\mu = 0.35$

Therefore, the minimum coefficient of friction required is 0.35.

I hope it helps you!

4 0

3 years ago

Three identical capacitors are connected in parallel to a battery. if a total charge of q flows from the battery, how much charg

muminat

Each capacitor carry the same charge 'q'.

Discussion:
The voltage from the battery is distributed equally across all of the capacitors when they are linked in series. The three identical capacitors' combined voltage is computed as follows:

$V_{T}$ = V₁ +V₂ +V₃

This voltage may also be calculated using capacitance and charge;

V = Q/ C

$V_{T}$ = V₁ +V₂ +V₃

Provided that the total charge is 'q', hence the total voltage can be expressed as:

$V_{T}$ = (Q/C₁) + (Q/C₂) + (Q/C₃) = Q(1/C₁ +1/C₂ +1/C₃)

Therefore from the above explanation, it is concluded that each and every capacitor carry same charge 'q'.

Learn more about the capacitor here:

brainly.com/question/17176550

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7 0

1 year ago

PLS ANSWER FAST WILL GIVE BRAINLY TIMED TEST

solong [7]

A=F/m
a=(3000000)/(20000)
a=15 m/s^2

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2 years ago

HELP PLEASE I REALLY NEED THE ANSWERS​

HELP PLEASE I REALLY NEED THE ANSWERS