Complete question is;. A 73mH solenoid inductor is wound on a form that is 0.80m long and 0.10m in diameter a coil having a resistance of 7.7 ohms is tightly wound around the solenoid at its center the mutual inductance of the coil and solenoid is 19μH at a given instant the current in the solenoid is 820mA and is decreasing at the rate of 2.5A/s at the given instant what is the induced current in the coil
Answer:
6.169 μA
Explanation:
Formula for induced EMF is given by the equation;
EMF = M(di/dt). We are given;
di/dt = 2.5 A/s
M = 19μH = 19 × 10^(-6) H
Thus;
EMF = 19 × 10^(-6) × 2.5.
EMF = 47.5 × 10^(-6) V
Formula for current is;
i = EMF/R. R is resistance given as 7.7 ohms.
Thus; i = 47.5 × 10^(-6)/7.7
i = 6.169 μA
Answer:
The best single equation in order to fin the acceleration is
Explanation:
The best single equation in order to find the acceleration is the following kinematics equation:
As the rocket start from the rest, the initial velocity value is zero. Then the acceleration value is:
Let us say that triangle XYZ has sides of XY, YZ, and ZX.
Each of the corners X, Y, and Z are located at their own
(x, y) points.
If all of the triangle are transformed through
translation by a movement of 2 units left and 1 unit down on the coordinate
plane then we generate a triangle X’Y’Z’.
Then each of the corners X’, Y’ and Z’ are now located at
(x – 2, y – 1) coordinates.
Since all of the corners were moved then we can also say
that:
XY is congruent to X’Y’
YZ is congruent to Y’Z’
ZX is congruent to Z’X’
Since all sides are congruent, therefore all angles are
also congruent.
Therefore the measure of angle x’ is equal to the measure
of angle x.
Answer:
<span>40 degrees</span>
