Answer:
F = 4856.32 N
Explanation:
Given,
A satellite is orbiting earth at a distance from Earth surface, h = 35000 m
The mass of the satellite, m = 500 Kg
The radius of the Earth, R = 6.371 x 10⁶ m
The mass of the Earth, M = 5.972 x 10²⁴ Kg
The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²
The force between the Earth and the satellite is given by the formula
F = GMm/(R+h)² N
Substituting the values in the above equation
F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²
= 4856.32 N
Hence, the force between the planet and the satellite is, F = 4856.32 N
Answer:
counterclockwise

Explanation:
= Small drive wheel radius = 2.2 cm
= Angular acceleration of the small drive wheel = 
= Radius of pottery wheel = 28 cm
= Angular acceleration of pottery wheel
As the linear acceleration of the system is conserved we have

The angular acceleration of the pottery wheel is
.
The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.
= Initial angular velocity = 0
= Final angular velocity = 
t = Time taken
From the kinematic equations of linear motion we have

The time it takes the pottery wheel to reach the required speed is 
Answer:
I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps
Explanation:
May I have brainliest please? :)
Acids are danger so stay away
This question is incomplete
Complete Question
Three equal point charges are held in place as shown in the figure below
If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.
A) F1=2F2
B) F1=3F2
C) F1=4F2
D) F1=9F2
Answer:
D) F1=9F2
Explanation:
We are told in the question that there are three equal point charges.
q, Q1, Q2 ,
q = Q1 = Q2
From the diagram we see the distance between the points d
q to Q1 = d
Q1 to Q2 = nd
Assuming n = 2
= 2 × d = 2d
Sum of the two distances = d + 2d = 3d
F1 is the force on q due to Q1 and
F2 is the force on q due to Q2,
Since we have 3 equal point charges and a total sum of distance which is 3d
Hence,
F1 = 9F2