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Doss [256]
3 years ago
6

How long will it take a horse to go from rest to 19 km/hr if it is accelerating at 5 km/hr 2 ?

Physics
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps

Explanation:

May I have brainliest please? :)

Download pdf
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The 4th one is correct 
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4 years ago
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I need sum help on this
makkiz [27]
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If it took 3 hours to clean 6 houses, how many houses could be cleaned in 12 hours?
mel-nik [20]

Answer:

24

Explanation:

If it took 3 hours to clean 6 houses than you can figure that is 2 houses per hours. so if there are 12 hours and 2 houses an hour, you multiply 12x2 and get 24. Another way to do it is to use proportions (aka two fractions that equal eachother):

  3 hours                12 hours

----------------    =    ---------------

 6 houses          number of houses

To calculate this, we can think about how we go from 3 to 12. Well, 3x4 is 12, so we got to 12 by doing multiplying by 4. So we can multiply 6 by 4 and you get 24.

<u><em>Hope it helps! have a great day :)</em></u>

8 0
3 years ago
Read 2 more answers
A driver in a 2144 kg car traveling at 15 m/s hits the brakes, coming to a stop in 67 meters. How far would it take the car to s
Komok [63]
1) First, let's calculate the value of deceleration a that the car can achieve, using the following relationship:
2aS = v_f^2-v_i^2 = -v_i^2
where S=67 m is the distance covered, vf=0 is the final velocity of the car, and vi=15 m/s is the initial velocity. From this we can find a:
a= \frac{-v_i^2}{2S}= \frac{-(15m/s)^2}{2\cdot 67 m}=-1.68 m/s^2

2) Then, we can assume this is the value of acceleration that the car is able to reach. In fact, the force the brakes are able to apply is
F=ma
This force will be constant, and since m is always the same, then a is the same even in the second situation.

3) Therefore, in the second situation we have a=-1.68 m/s^2. However, the initial velocity is different: vi=45 m/s. Using the same formula of point 1), we can calculate the distance covered by the car before stopping:
2aS=-v_i^2
S= \frac{-v_i^2}{2a} = \frac{-(45 m/s)^2}{2\cdot (-1.68 m/s^2)}=603 m
4 0
3 years ago
if mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion​
11111nata11111 [884]

Answer:

See explanations below

Explanation:

According to Newtons second law of motion

F = mass * acceleration

F = ma

If mass of an object is decreased to half, then m₂ = 1/2 m

If acting force is reduced by quarter, then F₂ = 3/4 F

F₂ = m₂a₂

3/4F = 1/2m a₂

Divide both expressions

(3/4F)/F = (1/2m)a₂/ma

3/4 = 1/2a₂/a

3/4 = a₂/2a

4a₂ = 6a

2a₂ = 3a

a₂ = 3/2 a

Hence the acceleration of its motion will be one and a half of its original acceleration.

8 0
3 years ago
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