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mr Goodwill [35]
2 years ago
10

Bill drives west at 20\, \dfrac{\text m}{\text s}20 s m ​ 20, start fraction, start text, m, end text, divided by, start text, s

, end text, end fraction, then slows to a stop at the red light. A graph of his velocity over time is shown below, where eastward is the positive velocity direction.
Physics
2 answers:
lara [203]2 years ago
7 0

Answer:

This

Explanation:

Khan academy answer

vovangra [49]2 years ago
4 0

Answer:

Positive Horizontal line, constant

Explanation:

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Jobisdone [24]
Hey!!

here is your answer >>>

We know that, acids and strong bases are good conductors of electricity!. And gold conducts electricity , while the best is silver and niext comes gold!. And H20 which is water contains less ions , so it is not a good conductors , it is a conductors but not a good conductor!. Salt in it's solid for cannot produce ions, hence, it cannot conduct electricity , but when this salt is mixed with water or when it is in it's molten state it can conduct electricity!. So now,the answer for the question is ,

B) III and IV only!.

Hope my answer helps!
7 0
3 years ago
Read 2 more answers
Someone please helpppp!
Vlad1618 [11]
I believe it’s A, i could be wrong tho 3
8 0
3 years ago
Does a paddle boat’s wheel rotate clockwise or counterclockwise? PLS HELP
finlep [7]

Answer:

clockwise and counter clockwise

it depends wich way you start paddling

6 0
3 years ago
What is the standard measurement system used by scientists around the world?
sleet_krkn [62]

Answer:

Hey mate....

Explanation:

This is ur answer....

<h3><em>The International System of Units (SI), commonly known as the metric system, is the international standard for measurement.</em></h3>

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5 0
3 years ago
Read 2 more answers
A 4.00-kg block hangs by a light string that passes over a massless, frictionless pulley and is connected to a 6.00-kg block tha
Anna007 [38]

Answer:

v = 2.82 m/s

Explanation:

For this exercise we can use the conservation of energy relations.

We place our reference system at the point where block 1 of m₁ = 4 kg

starting point. With the spring compressed

        Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂

final point. When block 1 has descended y = - 0.400 m

        Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y

as there is no friction, the energy is conserved

       Em₀ = Em_f

       ½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y

       ½ k x² - m₁ g y = ½ m₂ v²

 

       v² = \frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y

let's calculate

        v² = \frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)

        v² = 2.7 + 5.23

        v = √7.927

        v = 2,815 m / s

using of significant figures

        v = 2.82 m/s

5 0
3 years ago
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