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mr Goodwill [35]
2 years ago
10

Bill drives west at 20\, \dfrac{\text m}{\text s}20 s m ​ 20, start fraction, start text, m, end text, divided by, start text, s

, end text, end fraction, then slows to a stop at the red light. A graph of his velocity over time is shown below, where eastward is the positive velocity direction.
Physics
2 answers:
lara [203]2 years ago
7 0

Answer:

This

Explanation:

Khan academy answer

vovangra [49]2 years ago
4 0

Answer:

Positive Horizontal line, constant

Explanation:

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Is the physical phenomena arising from the force caused by magnet  objects that produce fields that attract or repel other objects while magnetic field is a region around the magnetic material or a moving electric charge within the force of magnetism acts 
 
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3 years ago
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Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.
Rom4ik [11]

Answer:

<em>50%</em>

Explanation:

Given

Initial power = 200W

Final power = 300W

Increment = 300 - 200 = 100W

percentage increase = increment/initial power * 100

percentage increase = 100/200 * 100%

percentage increase = 0.5 * 100

percentage increase = 50%

<em>Hence the percentage increase in speed is 50%</em>

6 0
2 years ago
A speeder is pulling directly away and increasing his distance from a police car that is moving at 24 m/s with respect to the gr
iogann1982 [59]
2,062,305 2,062,305 <span>2,062,305</span>
8 0
2 years ago
When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam
Len [333]

Answer:

Explanation:

Given that,

Mass of the heavier car m_1 = 1750 kg

Mass of the lighter car m_2 = 1350 kg

The speed of the lighter car just after collision can be represented as follows

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\frac{(1850)(1.4)+(1450)(-1.10)-(1850)(0.250)}{1450} \\\\=\frac{2590+(-1595)-(462.5)}{1450} \\\\=\frac{2590-1595-462.5}{1450} \\\\=\frac{532.5}{1450}\\\\=0.367m/s

b) the change in the combined kinetic energy of the two-car system during this collision

\Delta K.E=(\frac{1}{2} m_1v_1^2+\frac{1}{2} m_2v_2^2)-(\frac{1}{2} m_1u_1^2+\frac{1}{2} m_2u_2^2)\\\\=\frac{1}{2} (m_1(v_1^2-u_1^2)+m_2(v_2^2-u_2^2))

substitute the value in the equation above

=\frac{1}{2} (1850((0.250)^2-(1.4)^2)+(1450((0.3670)^2-(-1.10)^2)\\\\=\frac{1}{2}(11850(0.0625-1.96)+(1450(0.1347)-(1.21))\\\\= \frac{1}{2}(11850(-1.8975))+(1450(-1.0753))\\\\=\frac{1}{2} (-3510.375+(-1559.185)\\\\=\frac{1}{2} (-5069.56)\\\\=-2534.78J

Hence, the change in combine kinetic energy is -2534.78J

8 0
3 years ago
Determine e when I = 0.50 A and R = 12 W.
sammy [17]

Answer:

The correct answer is "24 V".

Explanation:

The given values are:

Current,

I = 0.50 A

Resistance,

R = 12 W

As we know,

⇒ I = 0.5\times (\frac{E}{2R})

On substituting the given values, we get

⇒ 0.5= (\frac{E}{4\times 12} )

⇒ 0.5= (\frac{E}{48} )

⇒   E=24 \ V  

7 0
3 years ago
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