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katen-ka-za [31]
3 years ago
12

What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Mathematics
2 answers:
LiRa [457]3 years ago
7 0
(2,-16) should be the answer
Mice21 [21]3 years ago
6 0

Answer:

vertex = (2, - 16)

Step-by-step explanation:

given

f(x) = (x - 6)(x + 2) ← equate to zero to find the zeros

(x - 6)(x + 2) = 0

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 2 = 0 ⇒ x = - 2

The vertex lies on the axis of symmetry which is situated at the midpoint of the zeros, hence

x_{vertex} = \frac{6-2}{2} = \frac{4}{2} = 2

Substitute x = 2 into f(x) for corresponding y- coordinate of vertex

f(2) = (2 - 6)(2 + 2) = - 4 × 4 = - 16

vertex = (2, - 16)

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Answer:

<h2>A) 3 cm</h2>

Step-by-step explanation:

The formula of a volume of a cylinder:

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We have r = 1cm and H = 21cm. Substitute:

V=\pi(1^2)(21)=21\pi\ cm^3

The formula of a cone:

V=\dfrac{1}{3}\pi r^2H

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We have V = 21π cm³ and H = 7cm. Substitute:

\dfrac{1}{3}\pi(r^2)(7)=21\pi        <em>divide both sides by π</em>

\dfrac{1}{3}(7)(r^2)=21         <em>divide both sides by 7</em>

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r^2=9\to r=\sqrt9\\\\r=3\ cm

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3 years ago
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Answer:

the graph will describe 13x+15 if the cost per audio book goes up by $1.00.

Step-by-step explanation:

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