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katen-ka-za [31]
3 years ago
12

What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Mathematics
2 answers:
LiRa [457]3 years ago
7 0
(2,-16) should be the answer
Mice21 [21]3 years ago
6 0

Answer:

vertex = (2, - 16)

Step-by-step explanation:

given

f(x) = (x - 6)(x + 2) ← equate to zero to find the zeros

(x - 6)(x + 2) = 0

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 2 = 0 ⇒ x = - 2

The vertex lies on the axis of symmetry which is situated at the midpoint of the zeros, hence

x_{vertex} = \frac{6-2}{2} = \frac{4}{2} = 2

Substitute x = 2 into f(x) for corresponding y- coordinate of vertex

f(2) = (2 - 6)(2 + 2) = - 4 × 4 = - 16

vertex = (2, - 16)

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