Let the width = X
The length would be X + 20
Area = Length x width:
2400 = x * (x+20)
Simplify:
2400 = x^2 + 20x
Subtract 2400 from both sides:
x^2 + 20x - 2400 = 0
Factor:
(x-40) (x+60) = 0
Solve for both x's:
x = 40 and x = -60
The dimensions of a parking lot have to be positive values so you would use x = 40.
The width = x = 40
The length = x +20 = 40+20 = 60
The dimension of the parking lot is 40H x 60H
9 times 21 is 189
the answer is 189 inches
Answer:
13
Step-by-step explanation:
Hope this helps.
This is a right triangle. To find the length of the hypotenuse a^2 + b^2 = c^2.
21^2 + 18^2 = c^2
441 + 324 = c^2
765 = c^2
27.66 km
The answer is -6/5
First convert the equation to y=mx+b form
you’ll get y=5/6x+27
then to find the line perpendicular to this equation, you have the flip the slope.
ending with -6/5