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serious [3.7K]
3 years ago
5

Mr. Leonard took a job through an employment agency. The job pays $88K per year. He must pay a fee to the employment agency. The

fee is 22% of his "rst four weeks’ pay. How much money must Mr. Leonard pay the agency, to the nearest cent? K = 1,000 88K = 88 × 1,000 = __________ annual salary Weekly salary = annual salary ÷ 52 Weekly salary = 88,000 ÷ 52 = __________ 4 weeks salary = 4 × 1,692.31 = __________ 22% of 4 weeks salary = 6,769.24 × 0.22 ≈ __________ Mr. Leonard must pay the agency __________.
Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
This question shows you how to determine the amount of money Mr. Leonard makes in 4 weeks.  It takes his total salary, divides it by 52 (there are 52 weeks in a year), then multiplies it by 4 (you need 4 weeks worth of pay). 

This amount is shown as $6769.24.

He must pay the agency 22% of this, so change 22% to 0.22 and multiply it by the amount he makes in 4 weeks.

0.22 x 6769.24 = $1489.23

Mr. Leonard must pay the agency $1489.23 after the first 4 weeks.
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Albert jumped 100 times in 97.5 seconds. Round off the time taken to the nearest second.​
KonstantinChe [14]
Answer
98 seconds
Step by step explanation
The reason being is that .5 would be millisecond and 5 will round up making the answer be 98 seconds
5 0
3 years ago
What is the simplified value of the exponential expression 16^1\4
Natalka [10]

If you observe that 16 = 2^4, you can rewrite the expression as

16^{\frac{1}{4}} = (2^4)^{\frac{1}{4}}

Now, if you use the exponent rule (a^b)^c = a^{bc}, you may rewrite the expression again:

(2^4)^{\frac{1}{4}} = 2^{4\cdot\frac{1}{4}} = 2^1 = 2

6 0
3 years ago
use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 )​, (15 comma
lyudmila [28]

Answer:

volume V of the solid

\boxed{V=\displaystyle\frac{125\pi}{12}}

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.  

Each slice is a quarter of cylinder 5/n thick and has a radius of  

-k(5/n) + 5  for each k = 1,2,..., n (see picture)

So the volume of each slice is  

\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}

for k=1,2,..., n

We then add up the volumes of all these slices

\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}

Notice that the last term of the sum vanishes. After making up the expression a little, we get

\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2

But

\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)

we also know that

\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}

and

\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}

so we have, after replacing and simplifying, the sum of the slices equals

\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}

and the volume V of our solid is

\boxed{V=\displaystyle\frac{125\pi}{12}}

3 0
3 years ago
Answer while showing work I need u to show ur work and answer
skad [1K]

Answer:

7cm

Step-by-step explanation:

One side of a square is increased by 8 cm, let us say the length got increased by 8 cm. So we have length of x + 8 cm

An adjacent side, the width, decreased by 2 cm. So we have width of x - 2cm

Perimeter of rectangle = 2(length + width)

40 = 2( (x + 8) + ( x - 2) )

40 = 2( 2x + 6)

40 = 4x + 12

28 = 4x

x = 7 cm

That is 7 cm of the length of the side of the square

4 0
3 years ago
At the beginning of each year for 14 years, Sherry Kardell invested $400 that earns 10% annually. What is the future value of Sh
Naddik [55]
Hmm if I'm not mistaken, is just an "ordinary" annuity, thus 

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\\\

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &400\\
r=rate\to 10\%\to \frac{10}{100}\to &0.1\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
\end{array}\to &1\\

t=years\to &14
\end{cases}
\\\\\\
A=400\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 14}-1}{\frac{0.1}{1}} \right]

3 0
3 years ago
Read 2 more answers
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