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MA_775_DIABLO [31]
3 years ago
13

Hii pls help me if u can tysm

Mathematics
1 answer:
natka813 [3]3 years ago
6 0

Answer:

she hit the flo'

next thing yk

shawdy got

low

low

low

low

low

low

low

Step-by-step explanation:

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A plumber's daily earnings have a mean of $145 per day with a standard deviation of $16.50.
avanturin [10]

Step-by-step explanation:

The plumber's daily earnings have a mean of $145 per day with a standard deviation of

$16.50.

We want to find the probability that the plumber earns between $135 and

$175 on a given day, if the daily earnings follow a normal distribution.

That is we want to find P(135 <X<175).

Let us convert to z-scores using

z =  \frac{x -  \mu}{ \sigma}

This means that:

P(135  \: <  \: X  \: <  \: 175) = P( \frac{135 - 145}{16.5}  \: <  \:  z \:  <  \frac{175 - 145}{ 16.5} )

We simplify to get:

P(135  \: <  \: X  \: <  \: 175) = P(  - 0.61\: <  \:  z \:  <  1.82 )

From the standard n normal distribution table,

P(z<1.82)=0.9656

P(z<-0.61)=0.2709

To find the area between the two z-scores, we subtract to obtain:

P(-0.61<z<1.82)=0.9656-0.2709=0.6947

This means that:

P(135  \: <  \: X  \: <  \: 175) =0.69

The correct choice is C.

7 0
3 years ago
How many swimmers are holding exaclty 3 toy whales? ​
Setler79 [48]
About 40 swimmers maybe more
6 0
3 years ago
10TH GRADE GEOMETRY, REAL ANSWERS PLS. HELP :)
lisov135 [29]
(B) is the right answer
5 0
3 years ago
Read 2 more answers
3x+4y+z=-2<br> 2y+3z=-8<br> z=-3
masya89 [10]

Answer:

z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3

3 0
3 years ago
Read 2 more answers
Help me, please......
denpristay [2]

Answer:

(x, y ) → (x - 4, y + 8 )

Step-by-step explanation:

4 units left in the x- direction means subtract 4 from the x- coordinate

8 units up in the y- direction means add 8 to the y- coordinate

Then the translation rule is

(x, y ) → (x - 4, y + 8 )

3 0
2 years ago
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