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Alexxx [7]
3 years ago
8

Plz answer this is urgent.​

Mathematics
2 answers:
choli [55]3 years ago
6 0

Answer:

2y subtracted from 9

I hope this answer is correct.

sergiy2304 [10]3 years ago
3 0

Answer: 9 subtracted from y and multiplied by 2

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3 with an exponent of 3 plus 4 with an exponent of 2
Andrej [43]

Hello! our answer here is going to be:

43.

Lets understand this a little better!

when dealing with exponents, it is the base number (3) times its self how ever many the above number is (3 again)

so, it wont be 3 x 3, but instead 3 x 3 x 3 because that's how much the exponent is.

same rule applies with 4^2!

8 0
3 years ago
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Which expressions are equivalent to the expression 7(5 + m) – 8? Check all that apply. 7m + 27 34m 35 + m – 8 35 + 7m – 8 75 + m
neonofarm [45]

7(5 + m) - 8 is equivalent to 35 + 7m - 8.

7(5+m)-8, multiply 7 with 5 and m and you get 35 + 7m - 8 which is also equal to 27 - 7m.

//Hope this helps.

8 0
4 years ago
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How many solutions does the system have?
Hatshy [7]
Answer:
A:One Solution
Step-by-step explanation:
First substitute the y in the first equation with the second equation to get
-2x-4=3x+3
since theres a variable of both sides, you subtract the variable with the least coefficient, in this case, you add 2x to both sides to get
-4=5x+3
subtract the constant on both sides to get
-1=5x
divide both sides by 5
x= -0.2 or -1/5
it's A, one solution
7 0
3 years ago
The number of fruit snacks available per student varies inversely with the number of students. There are 10 fruit snacks for eac
natka813 [3]

Answer:

240 fruit snacks

Step-by-step explanation:

if there's 10 for every student you do 10 times 24 to get 240

5 0
3 years ago
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An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers.​ So, 10 adult male passengers can have a m
disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that \mu = 160, \sigma = 35

Sample of 10:

This means that n = 10, s = \frac{35}{\sqrt{10}} = 11.07

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{158 - 160}{11.07}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0
3 years ago
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