1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
4 years ago
15

If a device uses 280 watts of power a day, about how many kilowatt-hours will it use in 30 days?

Physics
2 answers:
Pie4 years ago
6 0

dont answer 8.4, its wrong

Plato

kvasek [131]4 years ago
4 0
Given: 280 watts power a day
            
Unknown: KwH=?in 30 days
Solution: 280 watt-hours per day/1000x30 days
               .28 x 30=n
Answer:8.4 kwh
You might be interested in
A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.
strojnjashka [21]

Answer:

D=99.4665307m \approx 99.5m

Explanation:

From the question we are told that

Mass  m=6kg

Velocity of mass  V_m=16

Force of Tunnel  F_t=8N

Length of Tunnel L_t=1.6

Height of frictional incline H_i=2.9

Angle of inclination  \angle =16 \textdegree

Acceleration due to gravity  g=9.8m/s^2

First Frictional surface has a coefficient  \alpha_1 =0.21\ for\ d_c=1

Second Frictional surface has a coefficient \alpha _2=0.1

Generally the initial Kinetic energy is mathematically given by

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}(6)(16)^2

K.E=768

Generally the work done by the Tunnel is mathematically given as

w_t=F_t*d_t

w_t=8*1.6

w_t=12.8J

Therefore

Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t

E_t=K.E+E_t\\E_t=768J+12.8J

E_t=780.8J

Generally the energy lost while climbing is mathematically given as

E_c=mgh

E_c=(6)(9.8)(2.9)

E_c=170.52J

Generally the energy lost to friction is mathematically given as

E_f=\alpha *m*g*cos\textdegree*d_c

E_f=0.21*6*9.8*cos16*1

E_f=11.86965942 \approx 12J

Generally the energy left in the form of mass Em is mathematically given as

E_m=E_t+E_c+E_f

E_m=(768J)-(170.52)-(12)

E_m=585.48J

Since

E_m=\alpha_2*g*m*d

Therefore

It slide along the second frictional region

D=\frac{585.46}{0.1*9.81*6}

D=99.4665307m \approx 99.5m

6 0
3 years ago
A car uses ____________________________ to move. Select one: a. energy b. pulls c. motion d. work
Fynjy0 [20]

Answer:

Option A.

Explanation:

The correct answer is Option A.

The car uses energy to move.

A car is a machine that converts energy locked in fuel like petrol or diesel and turn it into mechanical energy.

The energy produced from the combustion of gasoline is then used to move the shaft, which sends the power to the rear axle and the wheel starts to move.

4 0
4 years ago
An electric motor is traversed by 3.10²º electrons in 6 seconds. Determine the intensity of the current passing through the moto
Effectus [21]

Current is the amount of charged passed divided by elapsed time.

I = Q/Δt

I = current, Q = charge, Δt = elapsed time

We also know an electron has a charge of 1.6×10⁻¹⁹C, so let us find the total charge by multiplying this unit of charge by the total number of electrons:

Q = 1.6×10⁻¹⁹(3×10²⁰) = 48C

We also have Δt = 6s, so let's plug these values in to solve for I:

I = 48/6

I = 8A

4 0
3 years ago
calculate the work done to stretch an elastic string by 40cm if a force of 10N produces an extension of 4cm in it?
Charra [1.4K]
100N is how much work is needed 
4 0
3 years ago
A girl is sitting in a sled sliding horizontally along some snow (there is friction present). The mass of the girl is 28.4 kg an
Luden [163]

Answer:

-13,594 J

Explanation:

First of all, we have to find the acceleration of the girl+sled system. This can be found by using Newton's second law of motion:

F=ma

where:

F = -96 N is the net force (the force of friction) acting on the system

m = 28.4+15.3 = 43.7 kg is the total mass of the girl and the sled

a is their acceleration

Solving for a,

a=\frac{F}{m}=\frac{-96}{43.7}=-2.2 m/s^2

The negative sign means the sled is slowing down.

Now we can find the displacement of the sled during the deceleration phase, by using the suvat equation:

s=ut+\frac{1}{2}at^2

where

u = 41.8 m/s is the initial velocity

t = 3.76 s is the time

a=-2.2 m/s^2 is the acceleration

So,

s=(41.8)(3.76)+\frac{1}{2}(-2.2)(3.76)^2=141.6 m

Now we can find the work done by friction on the sled, which is given by:

W=Fs

where

F = -96 N is the force of friction

s = 141.6 m is the displacement of the sled+girl system

Solving,

W=(-96)(141.6)=-13,594 J

where the negative sign means the force is opposite to the displacement.

8 0
3 years ago
Other questions:
  • Many household cleaners, particularly toilet cleaners and some drain cleaners have acid in them. This is the equation representi
    11·2 answers
  • A bicycle is parked at the top of a hill. what form of energy does it possess?
    10·1 answer
  • Describe what would happen if anything to the mass and weight when you go to jupiter
    11·2 answers
  • Mateo drew the field lines around the ends of two bar magnets but forgot to label the direction of the lines with arrows. At lef
    14·2 answers
  • What are two ways in which scientists can show creativity ?
    10·2 answers
  • A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl
    10·1 answer
  • ANSWER:
    15·2 answers
  • Tech A says that as engines gain miles, the spark plug gap increases, which raises the ignition system’s available voltage. Tech
    13·1 answer
  • Sodium lamps give off light at
    11·2 answers
  • In the given figure, weight of stone inside water
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!