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love history [14]
3 years ago
6

An electric motor is traversed by 3.10²º electrons in 6 seconds. Determine the intensity of the current passing through the moto

r.​
Physics
1 answer:
Effectus [21]3 years ago
4 0

Current is the amount of charged passed divided by elapsed time.

I = Q/Δt

I = current, Q = charge, Δt = elapsed time

We also know an electron has a charge of 1.6×10⁻¹⁹C, so let us find the total charge by multiplying this unit of charge by the total number of electrons:

Q = 1.6×10⁻¹⁹(3×10²⁰) = 48C

We also have Δt = 6s, so let's plug these values in to solve for I:

I = 48/6

I = 8A

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Natalija [7]

Answer:

I think it is the answer A

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3 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


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3 years ago
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