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3 years ago

ANSWER:

Physics

2 answers:

Llana [10]3 years ago

7 0

Answer:

Reflected ray is B

Refracted ray is C

Explanation:

When a ray of light falls on a highly polished and smooth surface, it bounce back into the same medium. This phenomenon is called reflection.

According to the laws of reflection, the angle of incidence is equal to the angle of reflection. So, ray B is the reflected ray.

When a ray of light falls on the interface of two media, then after refraction the ray enters into another medium. This phenomenon is called refraction.

So, ray C is the refracted ray.

Novay_Z [31]3 years ago

5 0

If the light undergoes refraction at the interface, then the event is described by the rays A and C .

If the light undergoes reflection at the interface, then the event is described by the rays A and B .

Oops. I see that these are answers. Somehow I must have stumbled onto the set of Jeopardy.

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Which statement describes a characteristic of a question that can be answered through scientific inquiry? A. It can be answered

saw5 [17]

Answer:

the correct one is D

Explanation:

A question that can be answered with a scientific investigation must be a question where measurements of some kind can be made and with these measurements check that the question is correct or not.

When examining the answers the correct one is D

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3 years ago

An electron that has a velocity with x component 1.6 × 106 m/s and y component 2.4 × 106 m/s moves through a uniform magnetic fi

Sergio039 [100]

Answer:

(a) 5.056 x 10^-14 N

(b) 5.056 x 10^-14 N

Explanation:

X component of velocity of electron is 1.6 × 10^6 m/s

Y component of velocity of electron is 2.4 × 10^6 m/s

X component of magnetic field is 0.025 T

Y component of magnetic field is -0.16 T

charge on electron, q = - 1.6 x 10^-19 C

Write the velocity and magnetic field in the vector forms.

$\overrightarrow{v}=1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j}$

$\overrightarrow{B}=0.025\widehat{i}-0.16\widehat{j}$

The force on the charge particle when it is moving in the magnetic field is given by

$\overrightarrow{F}=q\left ( \overrightarrow{v}\times \overrightarrow{B} \right )$

(a) Force on electron is given by

$\overrightarrow{F}=-1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

$\overrightarrow{F}=5.056\times 10^{-14}\widehat{k}$

Magnitude of force is 5.056 x 10^-14 N.

(b) Force on a proton is given by

$\overrightarrow{F}=1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

$\overrightarrow{F}=-5.056\times 10^{-14}\widehat{k}$

Magnitude of force is 5.056 x 10^-14 N.

Thus, the magnitude of force remains same but the direction of force is opposite to each other.

Explanation:

4 0

3 years ago

Changes in the forms of energy are called

Dima020 [189]

Changes in the forms of energy are called "Energy Conversions"

Hope this helps!

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3 years ago

Put the phase of mitosis or mitosis in order from first to last

vladimir1956 [14]

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3 years ago

Read 2 more answers

A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per

FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

4 0

3 years ago