Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
The first side is 10 inches
the side parallel to this is (10×2)= 20 inches
Height is half the length=1/2×20=10 inches
The area of trapezium is given by:
Area=1/2×h×(a+b)
where a and b are the sides, h is the height. Thus the area will be:
Area=1/2×10×(20+10)
=1/2×10×30
=150 sq. inches
Answer:C
Step-by-step explanation:
Bc there's 3 does below and 3 dots above
i really thinks its 6.9*10 to the power of 2
