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Sav [38]
2 years ago
11

What is the zero of the function

Mathematics
2 answers:
SpyIntel [72]2 years ago
8 0

Answer:

A

Step-by-step explanation:

The zero is the value of x where the line crosses the x- axis

The line crosses the x- axis at x = - 5 ← zero

Shtirlitz [24]2 years ago
4 0

Answer:

-5

Step-by-step explanation:

The zero of a function is the x-value of the location where the function intersects the x-axis.

Here I read at (-5,0), the function intersects the x-axis, so the zero of the functiion is x = -5

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A cylinder has volume 45 pie and radius 3. What is its height?
liraira [26]

Answer:

5 units

Step-by-step explanation:

The <u>volume of the cylinder</u> is the area of the circle multiplied by it's height. Therefore, the volume of the cylinder is πr² × h, which when simplified, gives us πr²h. Let's substitute the volume and the radius in the formula to find the height.

⇒ πr²h = Volume of cylinder

⇒ (π)(3²)(h) = 45π

Now, simplify the equation to evaluate the area of the cylinder.

⇒ (π)(3²)(h)/(3²)(π) = 45π/(3²)(π)

⇒ (h) = 45π/(9)(π) = 45/(9) = 5 units

7 0
2 years ago
Can someone solve this? Im lost .......
Westkost [7]
A.; 14 doesn’t work and neither does 8 or 3.
5 0
2 years ago
E. It costs $1.50 per hour to dry clothes at a laundromat. The rate per hour is $1.50 (slope) and the beginning point is 0 (y-in
klemol [59]

Answer:

y=1.5x

b is the y intercept but it is 0 so no need to add it. y is the result

5 0
2 years ago
Evaluate −8 + 10 × 4 ÷ (−2).
vivado [14]
-28 have a great day mark me brainiest!!
7 0
2 years ago
Read 2 more answers
NEED THIS DONE ASAP!! Thank you!!​
g100num [7]

Answer:

\overset{\frown}{WX}= 66^{\circ}

Step-by-step explanation:

<u>Inscribed Angle Theorem</u>

The measure of an <u>inscribed angle</u> is half the measure of the <u>intercepted arc</u>.

First, use the Inscribed Angle Theorem to calculate the measure of arc WY.

  \displaystyle \angle WXY=\dfrac{1}{2} \overset{\frown}{WY}

\implies 57^{\circ}=\dfrac{1}{2} \overset{\frown}{WY}

\implies \overset{\frown}{WY}= 2 \cdot 57^{\circ}

\implies \overset{\frown}{WY}= 114^{\circ}

Assuming XY is the diameter of the circle:

\implies \overset{\frown}{WY}+ \overset{\frown}{WX}= 180^{\circ}

\implies 114^{\circ} + \overset{\frown}{WX}= 180^{\circ}

\implies \overset{\frown}{WX}= 180^{\circ} - 114^{\circ}

\implies \overset{\frown}{WX}= 66^{\circ}

7 0
2 years ago
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