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Bumek [7]
3 years ago
7

An individual who has automobile insurance from a certain company is randomly selected. Let y be the number of moving violations

for which the individual was cited during the last 3 years. The pmf of Y is the following: 1 0.20 2 0.30 0.05 y 0 P(V) 0.45 (a) Compute E(Y). E(Y) = (b) Suppose an individual with Y violations incurs a surcharge of $80V. Calculate the expected amount of the surcharge,
Mathematics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

a) E(Y)= \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:    

E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95

b) E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".  

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).  

And the standard deviation of a random variable X is just the square root of the variance.  

Solution to the problem

Part a

We have the following distribution function:

Y        0         1         2       3

P(Y)  0.45    0.2    0.3   0.05

And we can calculate the expected value with the following formula:

E(Y)= \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:    

E(Y) = 0*0.45 +1*0.2 +2*0.3 +3*0.05= 0.95

Part b

For this case the new expected value would be given by:

E(80Y^2)= \sum_{i=1}^n 80Y^2_i P(Y_i)

And replacing we got

E(80Y^2) =80[ 0^2*0.45 +1^2*0.2 +2^2*0.3 +3^2*0.05]= 148

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A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
Without solving the equations which answer best describes the solutions.
telo118 [61]
ANSWER:
D. The answers will be different because after distributing the 4 in the first equation it will change the values.

Hope it helps u!
6 0
2 years ago
The value of y is directly proportional to the value of x If y=81 when x=54, what is the value of y when x=38
Arisa [49]

Answer:

y = 57

Step-by-step explanation:

y α x

y = kx ; k = Constant of proportionality

81 = k* 54

k = 81/54

k = 1.5

Value of y when x = 38

y = kx

y = 1.5 * 38

y = 57

Hence, y = 57 when x = 38

5 0
3 years ago
PLEASE HELP THIS IS DUE IN LIKE 5 MINS
Damm [24]
Answer:

-2.5

Solution:

-18.5/7.4=-2.5
7 0
3 years ago
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Everything you need is in the picture attached.

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