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Mama L [17]
3 years ago
7

What is the value of x4y , when x = 16 and y = 2? 132 2 223 4

Mathematics
3 answers:
algol133 years ago
8 0

Answer:

128

Step-by-step explanation:

We have the next multiplication:

x*4*y

We have the next information:

x=16

y=2

Now we can substitute the values of x and y in the multiplication:

16*4*2

And we can start multiplying by each number:

16*4=64

and then 64*2=128

The order of the multiplication does not affect the result.

klemol [59]3 years ago
6 0
X             y            4
16          2             4
16 x 2 x 4
16x 8
128

=128
shanarnia2 years ago
0 0

the answer would be 232 I hope I am right

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Need help with this quiz asap due by today
drek231 [11]

Answer:

5

Step-by-step explanation:

So first you need to what is over the four. 6x2=12/4. Okay so what does that equal? 12/4=3. Now we need to solve the first equation.  3+5=8. And the last part. 8-3=5

4 0
2 years ago
Read 2 more answers
Suppose j varies jointly with g and v, and j=1 when g=4 and v=5. what is j when g=10 and v=9?
Tems11 [23]
J\alpha gv
j=agv where a is a constant of proportionality.
j=1 when g=4 and v=5
1=a*4*5
1=20a
a=1/20
a= 0.05
j=0.05gv
When g=10 and v=9,
j=0.05*10*9
j=0.5*9
j=4.5
4 0
3 years ago
(a) The proportion of accidents that occur up to mile 1.2 of the path is the area under the density curve between 0 miles and 1.
inn [45]

Answer:

the area would be 0.4 or 40%

Step-by-step explanation:

The computation of the area is given below:

But before that the level of the density is

The density level is

=  1 ÷ (3 - 0)

= 1 ÷ 3

Area from 0 miles to 1.2 miles

= (1 ÷ 3) × (1.2 - 0)

= 0.4 or 40 %

Hence, the area would be 0.4 or 40%

the same is considered and relevant too

4 0
3 years ago
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
3 years ago
GIVING BRAINLIEST PLS HELP
AveGali [126]

Answer:

f(x) = x

Step-by-step explanation:

note : slope is positive 1, so the x term must be positive

also note the graph intersects the curve at y = 0, which means that they y-intercept is zero .

if we substitute this into the general equation for a line

y = mx + b, where m = +1 and b = 0,

we get y = x

or f(x) = x (in function form)

5 0
3 years ago
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