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Luda [366]
4 years ago
5

What is a solution for the inequality y-7<-12

Mathematics
2 answers:
gladu [14]4 years ago
5 0

Answer:

The answer is y is less than -5

Step-by-step explanation:

stiks02 [169]4 years ago
4 0

Answer:

y<-5

Step-by-step explanation:

y-7<-12

y<-5

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If f(x) = 2x + 1 and g(x) = x2 find g (f(3))
galben [10]

Answer:

g(f(3)) = 49

Step-by-step explanation:

Evaluate f(3), then substitute the value obtained into g(x) , that is

f(3) = 2(3) + 1 = 6 + 1 = 7, then

g(7) = 7² = 49

3 0
3 years ago
Cooper weights 20 pounds. When he is an adult dog, he will weigh about 315% of his current weight. Write 315% as a fraction and
Dahasolnce [82]

Answer:

3.15 and 3 3/20

Step-by-step explanation:

315 ÷ 100 = 3.15

3.15 = 3 3/20

Please mark me brainlest

8 0
3 years ago
What’s the inverse of y= 100 - x^2
Marianna [84]

Answer:

The inverse is ±sqrt(100-x)

Step-by-step explanation:

y= 100 - x^2

Exchange x and y

x = 100 -y^2

Solve for y

Subtract 100 from each side

x-100 = 100-100-y^2

x-100 = - y^2

Multiply by -1

-x+100 = y^2

100 -x = y^2

Take the square root of each side

±sqrt(100-x) = sqrt(y^2)

±sqrt(100-x) = y

The inverse is ±sqrt(100-x)

3 0
4 years ago
Read 2 more answers
What is the value for X and Y?
Snowcat [4.5K]

Answer:x is 65

y is 180

Step-by-step explanation:

Yo I'm not 100% percent sure but I think x is 65 and y is 180 .

I'm also doing edgudneuity.

7 0
4 years ago
Read 2 more answers
Someone plz help me with this asap!!!!!
Bas_tet [7]

Answer:

1.) x=8\sqrt{3};y=16

2.) x=1;y=\frac{\sqrt{3}}{2}

3.) x=28 ; y=14\sqrt{3}

4.) x=24 ; y=12\sqrt{3}

5.) x=4\sqrt{3};y=8\sqrt{3}

6.) x=\frac{8\sqrt{3}}{3};y=\frac{16\sqrt{3}}{3}

Step-by-step explanation:

Use the 30°-60°-90° formulas:

a. longer leg=\sqrt{3}*shorter leg

b. hypotenuse=2*shorter leg

1.) Insert values for a:

x=\sqrt{3}*8

Simplify:

x=8\sqrt{3}

Insert values for b:

y=2*8

Simplify:

y=16

2.) Insert values for a:

y=\sqrt{3}*\frac{1}{2}

Simplify:

y=\frac{\sqrt{3}}{2}

Insert values for b:

x=2*\frac{1}{2}

Simplify:

x=1

3.) Insert values for a:

y=\sqrt{3}*14

Simplify:

y=14\sqrt{3}

Insert values for b:

x=2*14

Simplify:

x=28

4.)Insert values for a:

y=\sqrt{3}*12

Simplify:

y=12\sqrt{3}

Insert values for b:

x=2*12

Simplify:

x=24

5.) Insert values for a:

12=\sqrt{3}*x

Divide both sides by \sqrt{3} and rationalize:

\frac{12}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{12}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{12}{\sqrt{3}}\\\\\frac{12\sqrt{3}}{\sqrt{9}}\\\\\frac{12\sqrt{3}}{3}\\\\4\sqrt{3}=x

Flip:

x=4\sqrt{3}

Insert values for b:

y=2*4\sqrt{3}

Simplify:

y=8\sqrt{3}

6.) Insert values for a:

8=\sqrt{3}*x

Divide both sides by \sqrt{3} and rationalize:

\frac{8}{\sqrt{3}}=\frac{\sqrt{3}*x}{\sqrt{3}}\\\\\frac{8}{\sqrt{3}}=x\\\\\frac{\sqrt{3}}{\sqrt{3}}*\frac{8}{\sqrt{3}}\\\\\frac{8\sqrt{3}}{\sqrt{9}}\\\\\frac{8\sqrt{3}}{3}=x

Flip:

x=\frac{8\sqrt{3}}{3}

Insert values for b:

y=2*\frac{8\sqrt{3}}{3}

Simplify:

y=\frac{16\sqrt{3}}{3}

Finito.

5 0
3 years ago
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