Question

WRITE IN VERTEX FORM1) y= x^2-2x+52)y= -2x^2-4x-11

Answer 1

Answer:

1) $y=(x-1)^2+4$

2) $y=-2(x+1)^2-9$

Step-by-step explanation:

The equation of the parabola in the vertex form is

$y=a(x-h)^2+k,$

where $(h,k)$ is the vertex of the parabola.

1) Given:

$y= x^2-2x+5$

Rewrite it as

$y=x^2-2x+1+4\\ \\y=(x-1)^2+4$

2) Given:

$y= -2x^2-4x-11$

Rewrite it as

$y=-2x^2-4x-2-9\\ \\y=-2(x^2+2x+1)-9\\ \\y=-2(x+1)^2-9$