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QveST [7]
4 years ago
10

WRITE IN VERTEX FORM1) y= x^2-2x+52)y= -2x^2-4x-11

Mathematics
1 answer:
Zielflug [23.3K]4 years ago
3 0

Answer:

1) y=(x-1)^2+4

2) y=-2(x+1)^2-9

Step-by-step explanation:

The equation of the parabola in the vertex form is

y=a(x-h)^2+k,

where (h,k) is the vertex of the parabola.

1) Given:

y= x^2-2x+5

Rewrite it as

y=x^2-2x+1+4\\ \\y=(x-1)^2+4

2) Given:

y= -2x^2-4x-11

Rewrite it as

y=-2x^2-4x-2-9\\ \\y=-2(x^2+2x+1)-9\\ \\y=-2(x+1)^2-9

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