Answer:
Nitrogen is limiting reactant and 30.4kg of ammonia can be formed
Explanation:
Nitrogen, N₂, reacts with hydrogen, H₂ to produce ammonia, NH₃, as follows:
2N₂ + 3H₂ → 2NH₃
<em>Where 2 moles nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia</em>
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To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles and the mass of ammonia formed as follows:
<em>Moles N2 -Molar mass: 28g/mol-</em>
50000g * (1mol / 28g) = 1786 moles N2
<em>Moles H2 -Molar mass: 2g/mol-</em>
10000g * (1mol / 2g) = 5000 moles H2
For a complete reaction of 5000 moles H2 are needed:
5000 mol H2 * (2mol N2 / 3mol H2) = 3333 moles N2. As there are just 1786 moles, Nitrogen is limiting reactant
The moles of ammonia that can be produced are 1786 moles because 2mol N2 = 2moles NH3.
The mass of ammonia -Molar mass NH3: 17g/mol- is:
1786 moles NH3 * (17g / mol) = 30362g =
30.4kg of ammonia can be formed
