Answer:
it's a day I think so ........
Answer:
Molar concentration is 0.050 M
Explanation:
Osmotic pressure -
Osmotic pressure is pressure applied to stop the flow of solvent across a semipermeable membrane, from its high concentration to its low concentration , it is a type of colligative property , i.e. , it depends on the number of moles of solute.
Osmotic pressure can be calculated from the formula -
π = CRT
π = Osmotic pressure ( in atm )
C = molarity of the solution
R = universal gas constant ( 0.082 L.atm / K.mol )
T = temperature ( Kelvin )
From the question ,
π = 945 torr
since,
760 torr = 1 atm
1 torr = 1 / 760 atm
945 torr = 1 / 760 * 945 atm
945 torr = 1.24 atm
Temperature = T = 28°C
(adding 273 To °C to convert it to K)
T = 28 + 273 = 301 K
Using the equation of osmotic pressure,
π = CRT
C = π / RT
putting the
C = 1.24 atm / 0.082 L.atm / K.mol * 301 K
C = 1.24 / 24.68
C = 0.050 M
Hence,
The Molar concentration is 0.050 M.
The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
<h3>Molarity of diluted solution (M₂) =....? </h3>
The molarity of the diluted solution can be obtained as follow:
<h3>M₁V₁ = M₂V₂</h3>
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
<h3>Divide both side by 3250</h3><h3 />
M₂ = 1050 / 3250
<h3>M₂ = 0.32 M</h3>
Therefore, the molarity of the diluted solution is 0.32 M
Learn more: brainly.com/question/22325751
