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kodGreya [7K]
3 years ago
13

How many grams are in 657 L of N2 gas at STP?

Chemistry
1 answer:
skad [1K]3 years ago
4 0

Answer:

821.25gm

Explanation:

volume = 657

no of mole = 657/22.4

mass = no of mole * molecular mass

mass = 657/22.4*28

= 821.25gm

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Use the balanced equation given below to solve the following problem; Calculate the volume in liters of CO produced by the react
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Answer: 40.3 L

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles

Sb_2O_3+3C\rightarrow 2Sb+3CO  

According to stoichiometry :

1 moles of Sb_2O_3 produces = 3 moles of CO

Thus 0.600 moles of Sb_2O_3 will produce=\frac{3}{1}\times 0.600=1.80moles  of CO

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If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
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Step 2: Calculate the rate of production of H₂

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