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Vladimir79 [104]
3 years ago
5

If half of a radioactive isotope decays in one hour, how much of the original isotope will remain after three hours?

Chemistry
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

1/8

Explanation:

Use logic,

every one hour, half of a radioactive remains

for the first hour, half remains

for the second hour, half of half remains or quarter remains

for the third hour, 1/2 of 1/2 of 1/2 or 1/8 remains

or use this equation

n = r ({ \frac{1}{2} })^{ \frac{f}{t} }

where

n = amount after f time

r = amount of the original isotope

f = time

t = half-life

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Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

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\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

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Assume an original volume of blood of one deciliter (100 ml). if 5 ml of oxygen diffuses into the blood, what would be its final
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