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balu736 [363]
3 years ago
14

Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x + 16 (k ∘ p)(x) = 2x2 − 16x + 32 (k

∘ p)(x) = 2x2 − 16x + 25 (k ∘ p)(x) = 2x2 − 11
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

<h2>(k ∘ p)(x) = 2x² - 16x + 25</h2>

Step-by-step explanation:

k(x) = 2x² - 7

p(x) = x - 4

To find (k ∘ p)(x) substitute p(x) into k(x),

that's replace any x in k(x) by p(x)

We have

(k ∘ p)(x) = 2(x - 4)² - 7

Expand

(k ∘ p)(x) = 2( x² - 8x + 16) - 7

= 2x² - 16x + 32 - 7

Simplify

We have the final answer as

<h3>(k ∘ p)(x) = 2x² - 16x + 25</h3>

Hope this helps you

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What is the remainder when the polynomial 6x2+11x−3 is divided by 2x−1?
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Answer: 4

There are three different ways to find the remainder.  Since I don't know which lesson you are working on, I will show you all three methods.

<u>Long Division:</u>

           <u>3x  +  7      </u>

2x - 1 ) 6x² + 11x - 3

       -  <u>(6x²  -  3x)</u>   ↓

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<u>Synthetic Division:</u>

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f(\frac{1}{2}) = 6(\frac{1}{2})² + 11(\frac{1}{2}) - 3

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      = 4

                                     

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