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balu736 [363]
3 years ago
14

Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x + 16 (k ∘ p)(x) = 2x2 − 16x + 32 (k

∘ p)(x) = 2x2 − 16x + 25 (k ∘ p)(x) = 2x2 − 11
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

<h2>(k ∘ p)(x) = 2x² - 16x + 25</h2>

Step-by-step explanation:

k(x) = 2x² - 7

p(x) = x - 4

To find (k ∘ p)(x) substitute p(x) into k(x),

that's replace any x in k(x) by p(x)

We have

(k ∘ p)(x) = 2(x - 4)² - 7

Expand

(k ∘ p)(x) = 2( x² - 8x + 16) - 7

= 2x² - 16x + 32 - 7

Simplify

We have the final answer as

<h3>(k ∘ p)(x) = 2x² - 16x + 25</h3>

Hope this helps you

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The cell labelled a is a joint frequency of 48 and the cell labelled b is a marginal frequency of 93.

<h3>What is a frequency table?</h3>

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Don’t be all up on me like that
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