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3 years ago

Which statement accurately describes the interaction between the poles of two bar magnets

Physics

2 answers:

marin [14]3 years ago

8 0

Answer: North Pole attracts a South Pole

Explanation:

Lorico [155]3 years ago

6 0

I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. "North and south poles attract each other" is the statement that <span>accurately describes the interaction between the poles of two bar magnets. I hope the answer has helped you.</span>

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A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate

Sladkaya [172]

Answer:

$P_2=4091\ KPa$

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

Power P =5.5 KW

mass flow rate

$\dot{m}= 0.01\ kg/s$

Lets take the exit temperature = T₂

We know that

$P=\dot{m}\ C_p (T_2-T_1)$

$5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K$

If we assume that process inside the compressor is adiabatic then we can say that

$\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{0.285}$

$\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\$

$2.88^{\frac{1}{0.285}}=\dfrac{P_2}{100}$

$P_2=40.91\times 100 \ KPa$

$P_2=4091\ KPa$

That is why the exit pressure will be 4091 KPa.

4 0

3 years ago

What term is used to denote the change of velocity with time

Westkost [7]

The answers is acceleration.

6 0

3 years ago

Read 2 more answers

Determine el valor del ángulo de tiro de un proyectil que tarda en impactar en 8s y que tuvo un alcance de 0,3km.

Gelneren [198K]

Answer:

$46.3^{\circ}$

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal direction (constant velocity)

- A uniformly accelerated motion along the vertical direction (constant acceleration)

The time of flight of a projectile is given by

$t=\frac{2u_y}{g}$

where

$u_y$ is the initial vertical velocity

$g=9.8 m/s^2$ is the acceleration due to gravity

Here the time of flight is

t = 8 s

So, the initial vertical velocity is:

$u_y=\frac{gt}{2}=\frac{(9.8)(8)}{2}=39.2 m/s$

At the same time, the horizontal distance covered by the projectile is given by

$d=u_x t$

where

$u_x$ is the horizontal velocity, which is constant

t is the time of flight

Here we know that the range of the projectile is 0.3 km, so

d = 0.3 km = 300 m

So the horizontal velocity is

$u_x=\frac{d}{t}=\frac{300}{8}=37.5 m/s$

Therefore, we can find the angle of projection of the projectile by using:

$\theta=tan^{-1}(\frac{u_y}{u_x})=tan^{-1}(\frac{39.2}{37.5})=46.3^{\circ}$

5 0

3 years ago

The coefficient of kinetic friction between Gary's shoes and the wet kitchen floor is 0.09. If Gary has a mass of 65 kg, what is

mariarad [96]

Answer:

57 N

Explanation:

Draw a free body diagram. There are three forces:

Weight force mg pulling down.

Normal force N pushing up.

Friction force F pushing horizontally.

Sum of the forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Friction force is the product of normal force and coefficient of friction:

F = Nμ

F = mgμ

F = (65 kg) (9.8 m/s²) (0.09)

F = 57.3 N

Rounded, the friction force is 57 N.

8 0

3 years ago

A flat roof is very susceptible to wind damage during a thunderstorm and/or tornado. If a flat roof has an area of 500 m2 and wi

Evgesh-ka [11]

Answer: The magnitude of the force exerted on the roof is 490522.5 N.

Explanation:

The given data is as follows.

Below the roof, $v_{1}$ = 0 m/s

At top of the roof, $v_{2}$ = 39 m/s

We assume that $P_{1}$ is the pressure at lower surface of the roof and $P_{2}$ be the pressure at upper surface of the roof.

Now, according to Bernoulli's theorem,

$P_{1} + 0.5 \times \rho \times v^{2}_{1} = P_{2} \times 0.5 \rho \times v^{2}_{2}$

$P_{1} - P_{2} = 0.5 \times \rho \times (v^{2}_{2} - v^{2}_{1})$

= $0.5 \times 1.29 \times [(39)^{2} - (0)^{2}]$

= $0.645 \times 1521$

= 981.045 Pa

Formula for net upward force of air exerted on the roof is as follows.

F = $(P_{1} - P_{2})A$

= $981.045 \times 500$

= 490522.5 N

Therefore, we can conclude that the magnitude of the force exerted on the roof is 490522.5 N.

5 0

3 years ago