Answer:
a. 600 ml, 12
Explanation:
The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.
The sum of exterior angles of a polygon = 360 degrees.
Exterior angle of a polygon = (360 ÷ number of sides)
Therefore,
Number of sides = 360 ÷ exterior angle
Exterior angle = 30 degrees
Hence,
Number of sides = 360 ÷ 30 = 12 sides
Since distance traveled of 50 miles is the same for each displacement ;
Total displacement = distance traveled * number of sides
Total displacement = 50 * 12 = 600 miles.
Answer:
GPS consist of the space segment, the control segment, and the user segments
If the speed is constant, the acceleration a must be zero. Since force F = m•a, the total force must be zero.
In a 1D case, work W is the product of force F and distance d: W = F • d.
Since there is no more information given about friction or air resistance, I have to assume you are looking for the work done by the total force, wich is also zero.
The approximate speed of sound is about 761 mph or 335.28 meters/second.
<h3>What's the approximate speed of sound?</h3>
If we consider the normal atmosphere at sea level, the speed of sound is about 761 mph or 335.28 meters/second. The speed of sound is different in different mediums such as solid and liquid.
So we can conclude that the approximate speed of sound is about 761 mph or 335.28 meters/second.
Learn more about speed here: brainly.com/question/4931057
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Answer:
![\phi=1.55 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D1.55%20%5BeV%5D)
Explanation:
We can use the work function equation for a photoelectric experiment:
- h is the plank constant
- c is the speed of light
- λ is the wave length
- K is the kinetic energy (or K=eΔV)
So we will have:
![\phi=3.64*10^{-19}[J]-0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D3.64%2A10%5E%7B-19%7D%5BJ%5D-0.728%20%5BeV%5D)
![\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D%283.64%2A10%5E%7B-19%7D%5BJ%5D%2A%5Cfrac%7B1eV%7D%7B1.6%2A10%5E%7B-19%7D%5BJ%5D%7D%29-0.728%20%5BeV%5D)
![\phi=2.28 [eV] - 0.728 [eV]](https://tex.z-dn.net/?f=%5Cphi%3D2.28%20%5BeV%5D%20-%200.728%20%5BeV%5D)
I hope it helps you!
