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EleoNora [17]
3 years ago
13

A car veers off course and runs straight into a brick wall. This is an example

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0
Short time large force
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The atoms in a sidewalk on a hot summer day are vibrating _____ the atoms in the sidewalk on a freezing day in winter.
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Answer:

(A) more rapidly than

Explanation:

With higher temperatures, object's molecules (and atoms) have higher kinetic energy which is due to faster "jiggling" (vibrations). On a hot day these vibrations in the material the sidewalk is made of are more rapid than on a cold day, just as their temperatures differ.

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When a ball rolls down a hill, what energy conversion occurs?
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C

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When a ball rolls down a hill, Potential Energy Conversion takes place to Kinetic Energy.

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3 years ago
A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static fr
PSYCHO15rus [73]

Answer:

ω = 2.1 rad/sec

Explanation:

  • As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.
  • This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.
  • Now, we need to ask ourselves: what supplies this force?
  • In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.
  • We know that this force can be expressed as follows:

       f_{frs} = \mu_{s} * F_{n} (1)

      where μs = coefficient of static friction between the rock and the merry-

      go-round surface = 0.7, and Fn = normal force.

  • In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:
  • Fn = m*g (2)
  • This static friction force is just the same as the centripetal force.
  • The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:

       F_{c} = m* \omega^{2}*r (3)

  • Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:

       \omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec

  • This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.
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3 years ago
A space station that does not rotate cannot simulate gravity for its occupants.
il63 [147K]

false

true

false

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true

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