Answer:
y(i) = h
v(y.i) = 0
Explanation:
See attachment for elaboration
a train has a velocity of 44 metre per second and an acceleration of 4 metre per second square. its velocity after 10 seconds is
1 answer:
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Answer:
t = 1.41 sec.
Explanation:
If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.
First, we need to find the value of acceleration, which is the same for both blocks.
If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:
F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)
⇒ a = ( = g/5 m/s²
Once we got the value of a, we can use for instance this kinematic equation, and solve for t:
Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.
As we know that force F makes an angle of 60 degree with X axis
so the X component is given as
now we have
Similarly we know that force F makes an angle of 45 degree with Y axis
so the X component is given as
now we have
Now for the component along z axis we know that
now plug in all components