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xxTIMURxx [149]
4 years ago
7

a train has a velocity of 44 metre per second and an acceleration of 4 metre per second square. its velocity after 10 seconds is

what​
Physics
1 answer:
myrzilka [38]4 years ago
7 0

Acceleration=Final velocity-Initial velocity /time.

Acceleration=a=4m/s².

Initial velocity= u= 44m/s

Final velocity=v= let it be v, since we are to look for the final velocity.

Time=t=10seconds.

Mathematically:

a=v-u/t

Substituting the givens into the equation.

4=v-44/10

cross multiply.

4×10 = v-44

40=v-44

40+44=v

v=84m/s

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A point charge with charge q1 = 4.00 μC is held stationary at the origin. A second point charge with charge q2 = -4.40 μC moves
Bezzdna [24]

Answer:

W=0.94J

Explanation:

Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.

This energy is given by:

U=\frac{K\left |q_1 \right |\left |q_2 \right |}{r}\\

So, the work done to move the chargue is:

W=U_1-U_2\\W=\frac{K\left |q_1 \right |\left |q_2 \right |}{r_1}-\frac{K\left |q_1 \right |\left |q_2 \right |}{r_2}\\r_1=\sqrt{((0.155 m)^2+0 m)^2}=0.115m\\r_2=\sqrt{((0.245 m)^2+(0.270 m)^2}=0.365m\\W=K\left |q_1 \right |\left |q_2 \right |(\frac{1}{r_1}-\frac{1}{r_2})\\W=8.99*10^9\frac{Nm^2}{c^2}(4.00*10^{-6}C)(4.40*10^{-6}C)(\frac{1}{0.115m}-\frac{1}{0.365})\\W=0.94J

The work is positive since the potential energy in 1 is greater than 2.

5 0
4 years ago
When droplets of water in the atmosphere act like prisms, the colors in sunlight undergo?
dexar [7]
White light is all the colours of light combined. When the droplets act like prisms, they split the white light into all its colours and also slightly bend the different colours. This is how a rainbow is formed.
4 0
3 years ago
An 5 kg object moving at 10 m/s will have a momentum equaling ____________.
Monica [59]

Answer:

50Kgm/s

Explanation:

Momentum=Mass*Velocity

P=mv

Given Mass=5Kg. Given Velocity=10m/s

Momentum=5*10=50Kgm/s

5 0
3 years ago
Help with these questions please?
iren2701 [21]

Three

The ray of light will come out of the glass at 90 degrees to the normal. What goes in is called the critical angle. At 90 degrees the ray will reflect rather than refract. This is just for interest.

<em><u>Formula</u></em>

n2 * sin(θ2) = n1* sin(θ1)

<em><u>Givens</u></em>

θ2 = 90 degrees

n2 = 1

n1 = ?

θ1 = 43.6

<em><u>Solution</u></em>

n1 * sin(43.6) = 1 * 1

n1 = 1/sin(43.6)

n1 = 1/0.6896

n1 = 1.45

Four

This problem is very instructive. It uses a little known trick so that you don't have to know the exact speed of light of one of the speeds. The other speed is compared to it. You could do it the long way and figure out the speeds in crown glass from air to the crown glass, and do the same thing with the other color. That would work. An easier way is not to bother. Call the speed of one of the colors = 1. Is the other speed greater or less than 1? We'll see.

The next thing you have to realize is that the speed is going to be  highest for either red or violet. That's because n is highest for violet and lowest for red. The intermediate colors don't matter. So the answer is either A or B.

They have n's between violet and red and so they will not be an answer. That means you can eliminate green and yellow (answers C and D).

<em><u>Formula</u></em>

v1/v2 = n2/n1

<em><u>Givens</u></em>

v1 = 1 (we'll say this is red)

v2 = ? (this is violet)

n2 = 1.62 for red. This is probably not exact, but it does not have to be. You just have to notice that violet is higher

n1 = 1.65 for violet. So you are trying to solve the relative speed of v2.

<em><u>Solution</u></em>

v1/v2 = n2/n1

1/v2 = 1.65/1.62      Cross multiply

1.65 * v2 = 1 * 1.62  Divide by 1.65

v2 = 1.62/1.65

v2 = 0.98

<em><u>Conclusion</u></em>.

The speed of violet is going to be slower than the speed of red.

Rule: the higher the index of refraction, the lower the speed.

Answer: red has the greater speed.

5 0
3 years ago
A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the gro
castortr0y [4]
Calculate velocity at halfway to the ground.

vfinal = root 2ad

v = root (2*9.81m/s^2*25)

v = 69.367175234 m/s

Kinetic energy = 1/2mv^2

Kinetic energy = 1/2 * (69.367175234 m/s^s^2

Ek = 2405.9025 Joules
4 0
3 years ago
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