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2 years ago

Help picture below problem 18

Mathematics

1 answer:

Natali [406]2 years ago

3 0

Solution :-

This triangle is a right angled triangle as we can see ∠POC, has a right angled sign. Now, we will assume the missing angle to be x, thus,

25° + 90° + x = 180° ( Angle sum property of a triangle )

115° + x = 180°

x = 180° - 115°

x = 65°

Thus, the measure of missing angle is 65°.

Hope that helps. :D

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Mary wants to find this product. 58 x 20 How can Mary find the product? A. 0 +16 + 100 B. 0 + 160 + 1000 . C. 58 + 16 + 100 D. 5

Fittoniya [83]

Answer:

Step-by-step explanation:

58×20=1160

0+160+1000=1160

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3 years ago

Activity 1 Calculate the following: 1. 68% of 418,

il63 [147K]

Answer:

284.24

Step-by-step explanation:

by multiplying 0.68 to 418 we get 68% of 418

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3 years ago

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Find the height of an equilateral triangle with sides of length 12

MAVERICK [17]

Answer:

Answer

sqrt(108)

6 sqrt(3)

10.3923

I don't know which answer you want.

Step-by-step explanation:

Drop a perpendicular from the top angle to the base.
The base is cut into 2 equal parts.
Each part is 12/2 = 6
The perpendicular, as its name implies, meets the base at 90o.
You can use the Pythagorean Theorem to find the height.

h^2 = side^2 - (1/2 b)^2

h^2 = 12^2 - 6^2

h^2 = 144 - 36

h^2 = 108

Take the square root of both sides

h = sqrt(108)

h = sqrt(2*2 * 3 * 3 * 3)

h = 2 * 3 sqrt(3)

h = 6sqrt(3)

h = 6 * 1.7321

h = 10.3923

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3 years ago

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Factor by grouping.......

Gekata [30.6K]

Answer:

A. (7n-1) (8n-1)

Step-by-step explanation:

56n^2 -8n-7n+1

56n^2 -8n -7n+1

Factor out 8n from the first group and -1 from the second group

8n (7n-1) -1(7n-1)

Factor out the (7n-1)

(7n-1) (8n-1)

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3 years ago

Determine if

Gnesinka [82]

The values of a and b are 1/4 and 1/5 respectively

<h3>How to determine the true statement?</h3>

The function is given as:

16x^2 - 25y^2 = 1

The above function is a horizontal hyperbola.

A horizontal hyperbola that passes through the origin is represented as:

$\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$

Rewrite 16x^2 - 25y^2 = 1 as

$\frac{x^2}{1/16} - \frac{y^2}{1/25} = 1$

By comparison, we have:

$a^2 = \frac{1}{16}$

$b^2 = \frac{1}{25}$

Solve for a and b

$a = \frac{1}{4}$

$b = \frac{1}{5}$

Hence, the values of a and b are 1/4 and 1/5 respectively