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3 years ago

Any answers on this?

Mathematics

2 answers:

anygoal [31]3 years ago

6 0

Perimeter is the distance all around the triangle, so take the side lengths and add them up in an expression.

(2x) + (4x - 2) + (3x - 1)

Combine like terms.

9x - 3

Your answer is D) 9x - 3.

Dafna11 [192]3 years ago

4 0

9x^3 -3 is the answer

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Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

monitta

Answer:

Decay

since 0.292 is less than 1

% rate of decrease

1 - 0.292 = 0.708

70.8%

4 0

2 years ago

What is 1/3 of eleven sixteenth

TiliK225 [7]

It’s 5 1/3 because 16 divided by 3 is 5 1/3

8 0

2 years ago

2 feet equal how many inches

djverab [1.8K]

To answer that it = 2 feet = 24 inches

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2 years ago

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Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

2 years ago

Need help ASAP PLZ PLZ PLZ

trasher [3.6K]

Answer:

I think B

Step-by-step explanation:

6 0

2 years ago

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