Answer:
4(2p−1)
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
The domain is t ≥ 0
The range is D ≥ 0
Step-by-step explanation:

D(t) = 100t + d₀
t is the time measured in hours.
d₀ is the initial position of the train.
We can assume the distance they go is not negative so...
The domain is t ≥ 0
The range is D ≥ 0
Answer:
-2<x<8
see below for graph
Step-by-step explanation:
First, we need to solve the inequality.
Inequality: |x-3|<5
Split into two equations:
x-3<5
x-3>-5 (notice how the sign is flipped when we make the number negative)
let's start with x-3<5
add 3 to both sides
x<8
now
x-3>-5
add 3 to both sides
x>-2
The graph is below
the intersection is the solution.
Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)
the equation is -2<x<8
Hope this helps!