Please answer quick! The best answer gets brainliest and 20 points.

There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051

BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events A and B are independent.

Step-by-step explanation:

The events are defined as follows:

A = a student in the class has a sister

B = a student has a brother

The information provided is:

N = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

The conditional probability of an event X provided that another event Y has already occurred is:

$P(X|Y)=\frac{P(A\cap Y)}{P(Y)}$

If the events X and Y are independent then,

$P(X|Y)=P(X)$

(1)

Compute the probability of event A as follows:

$P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286$

The value of P (A) is 0.4286.

(2)

Compute the probability of event B as follows:

$P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50$

The value of P (B) is 0.50.

(3)

Compute the probability of event A and B as follows:

$P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143$

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of B given A as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50$

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events A and B are independent.

6 0

3 years ago

Rounding factors to the greatest place results in this

san4es73 [151]

Estimate is the answer

3 0

2 years ago

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke

FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

8 0

3 years ago

Please help me!!!!!!!!!

nalin [4]

(y+20)=1(x+10); First, we can find the slope by using the equation y2-y1/x2-x1.

-9+20/1+10 (Accounting for double negatives).

11/11 = 1

The slope of the equation is 1, now we just need to pick a set of points from which we derived the slope from (doesn't matter which) as y1 and x1 in the point-slope equation. (y-y1)=m(x-x1)

Your final answer can either be (y+20)=1(x+10) or (y+9)=1(x-1) but in the context of this question it is (y+20)=1(x+10)

8 0

3 years ago

18 3/8f = -29 4/7 please help

KatRina [158]

Answer:

f=-552 /343 or 5=1 and 209/343

Step-by-step explanation:

4 0

3 years ago