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VladimirAG [237]
4 years ago
8

Exercise is mixed —some require integration by parts, while others can be integrated by using techniques discussed in the chapte

r on Integration.
∫(2x-1) ln (3x) dx.
Mathematics
1 answer:
amm18124 years ago
3 0

Answer:

ln(3x)-x²/2 + x +c

Step-by-step explanation:

∫(2x-1) ln (3x) dx can be computed with parts. The ln part can be made simpler be derivating, and integrating a polynomial wont hurt us that much.

We can derivate ln(3x) using the chain rule, the derivate of ln(x) is 1/x and the derivate of 3x is 3; therefore

(ln(3x))' = (1/3x)*3 = 1/x

A primitive of (2x-1) is, on the other hand, x²-x

Hence

∫(2x-1) = ln(3x) (x²-x) - ∫(x²-x)/x dx = ln(3x) (x²-x) - ∫(x-1) dx = ln(3x) (x²-x) - (x²/2 - x + k) = ln(3x)-x²/2 + x +c

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You have to do 45 divided by 2. Hopefully there is not tax!
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2 3/4 - 3/7<br><br> 10 points
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Give the value of x .<br><br> A. 60 degrees<br> B. 180 degrees<br> C. 120 degrees<br> D. 45 degrees
Harrizon [31]

Answer:

x=120°

Step-by-step explanation:

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2 years ago
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You have to make a cos graph that starts its minimum and of -2, has an amplitude of 10, a period of 10 and  a maximum of 18.
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lets start of with a regular cos(x) graph.  This starts on its maximum instead of minimum so we have to multiply it by -1 to get -cos(x) which does start on its minimum.

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