The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
21
is what I got on my calculator
Answer:
∠2 = 55°
Step-by-step explanation:
Given that the triangle has 2 congruent sides then the triangle is isosceles.
Thus the 2 base angle are congruent, both equal to ∠2
The sum of the 3 angles in a triangle = 180
7x + 6 + 7x + 6 + 70 = 180, that is
14x + 82 = 180 ( subtract 82 from both sides )
14x = 98 ( divide both sides by 14 )
x = 7
Hence
∠2 = 7x + 6 = (7 × 7) + 6 = 49 + 6 = 55°
Answer:
14
Step-by-step explanation:
18/2
9+5
<u>14</u>
