By the Pythagoras theorem, in a right triangle with the sides being a and b,
a² + b² = Hypotenuse²
Hypotenuse² = 4² + 4²
Hypotenuse² = 16 + 16 = 2*16
Hypotenuse = √2 * √16
Thus, hypotenuse = 4√2
Answer:
A 3SIDED shape
Step-by-step explanation:
Answer:

Step-by-step explanation:
From law of indices
Answer:
Part A)
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B)
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
----> equation A
----> equation B
substitute equation A in equation B



Find the value of x

Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B) How many did they EACH have at the end?

so


therefore
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Answer: ghrhuydduyfgjrguh
Step-by-step explanation:
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