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3 years ago

93 olds bravada 4 .3 liter with a code reading 82 what does this mean ,how to fix

Mathematics

1 answer:

puteri [66]3 years ago

4 0

93-82+(4.3) = 15.3

answer:15.3

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Math math math math math <br> i need help<br> tysm :) <3

stiv31 [10]

Answer:

C. x^14

Step-by-step explanation:

(x^9)^0 is 1

(x^7)^2 is x^14

x^14*1 is x^14

The Answer is C. x^14

Hope this helps!

5 0

3 years ago

If ∠A > ∠B, then what is the relation between AC and BC?<br>

prohojiy [21]

Answer:

ab and ac are congruent with each other

8 0

2 years ago

Read 2 more answers

The graph below shows the height through which an elevator travels, y, in x seconds: A graph is shown with x axis title as Time

Blababa [14]

Answer:

C. 10

Step-by-step explanation:

We are given a graph representing the height of the elevator with respect to time.

Since, we know that,

X-axis represents the 'time' in seconds and y-axis represents the 'height of the elevator' in feet.

As, the coordinate points on the graph are given by,

(1,10), (2,20), (3,30) and (4,40).

So, the rate of change can be found out by solving, $\frac{20-10}{2-1}=10$ .

Hence, the rate of change of the relationship is 10.

5 0

3 years ago

Read 2 more answers

Which number line shows an integer and its opposite?

emmasim [6.3K]

Answer:

Step-by-step explanation:

An integer is a whole number (not including 0). An integer's opposite can be found by adding a negative sign to the front of it. A negative integer's opposite would be positive, while a positive integer's opposite would be negative.

7 0

2 years ago

Find all the integers,b, that make up the trinomial x2 + bx + 10 factorable.

KonstantinChe [14]

By the fundamental theorem of algebra, we can write

$x^2+bx+10=(x-r_1)(x-r_2)$

Expanding the right hand side, we get

$x^2+bx+10=x^2-(r_1+r_2)x+r_1r_2\implies\begin{cases}r_1+r_2=-b\\r_1r_2=10\end{cases}$

We want $b$ to be an integer, which means $r_1,r_2$ must also be integers. This means $r_1,r_2$ must be factors of 10. There are several possibilities:

$r_1=\pm10,r_2=\pm1\implies b=-(10+1)=-11\text{ or }b=-(-10-1)=11$

$r_1=\pm5,r_2=\pm2\implies b=-(5+2)=-7\text{ or }b=-(-5-2)=7$

So there are 4 possible values for $b$ : -11, -7, 7, and 11.

7 0

3 years ago