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Blizzard [7]
4 years ago
7

Target is having a Back to School sale where all polo shirts are discounted by 20%. Joshua wants to buy five shirts: two cost $1

0.98 each, one costs $11.50, and two others cost $15.99 each. Joshua remembered he had a coupon in his pocket that would take an additional 30% of the shirts. Which choice represents the new total cost of the shirts including the sales tax of 6.5%
Mathematics
1 answer:
RUDIKE [14]4 years ago
7 0

Answer:

$39.03

Step-by-step explanation:

Joshua wants to buy five shirts:

  • two cost $10.98 each,
  • one costs $11.50,
  • two others cost $15.99 each.

Total cost of all shirts:

2\cdot\$10.98+\$11.50+2\cdot \$15.99=\$65.44

All polo shirts are discounted by 20%, then the total cost of all shirts is

\$65.44\cdot (1-0.2)=\$52.352

Joshua had a coupon in his pocket that would take an additional 30% of the shirts, then the total price will be

\$52.352\cdot (1-0.3)=\$36.6464

He has to pay sales tax of 6.5%, so the total price will be

\$36.6464\cdot (1+0.065)=\$39.028416\approx \$39.03

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The answer is 45 because if you divide 84 and 2 you get 42 and then add 3

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Solve 2(4 x + 3) < 5 x + 21. { x | x < 9} { x | x > -5} { x | x > -9} { x | x < 5}
Nesterboy [21]

Answer:

x <5

Step-by-step explanation:

2(4 x + 3) < 5 x + 21

Distribute

8x +6 < 5x +21

Subtract 5x from each side

8x -5x +6 < 5x-5x+21

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Subtract 6 from each side

3x+6-6 <21-6

3x <15

Divide each side by 3

3x/3 <15/3

x <5

5 0
3 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
Combine like terms.<br> - 2x - 14 = -3.- 1
UNO [17]

Answer:

combine -3-1

- 2x - 14 =  - 4

if you want to solve for x then you would move the -14 to the left buy adding 14 to both sides.

- 2x - 14 =  - 4 \\    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  + 14 \:  \:  + 14

your equation there will be

- 2x = 10

then you will divide -2 on both sides

\frac{ - 2x}{ - 2}  =  \frac{10}{ - 2}

finally x will equal

x =  - 5

3 0
3 years ago
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