1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liono4ka [1.6K]
3 years ago
10

Help this is due tomorrow​

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0
C 5/3 is the answer so it’s
You might be interested in
Determine the axis of symmetry and the vertex of the given function. y = 2x2 − 12x + 21 Axis of symmetry: x = Vertex: ( , )
Varvara68 [4.7K]
The vertex is (3,3) and the axis is 3
5 0
4 years ago
Read 2 more answers
Which value makes the equation 3x - 6 = 36 true?
steposvetlana [31]

Answer:

C) 14

Step-by-step explanation:

3x-6=36

3x=36+6

3x=42

x=42/3

x=14

3 0
2 years ago
56<br> х<br> 52<br> Can someone help ?
lions [1.4K]

The answer is =2,912

Step-by-step explanation:

56×52

=2,912

3 0
3 years ago
At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
42 = (80-20)e^{-3k} +20 \\  \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\  \\ k = -\frac{1}{3} ln (\frac{11}{30})

Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
8 0
3 years ago
I am in middle school
Svetlanka [38]

Answer:x\geq35/2

Step-by-step explanation:

4x-5\geq65

4x-5+5\geq65+5

4x\geq70

4x/4\geq 70/4

x\geq35/2

8 0
3 years ago
Other questions:
  • Two marbles, each with a mass of 10 g, are placed 5 m apart. What can said of the gravitational force between them?
    13·1 answer
  • How many squares can be made with 40 matchsticks
    10·1 answer
  • A cylindrical rain barrel with a diameter of 2.5 feet and a height of 3.5 feet is filled to a height of 1.5 feet. How many more
    13·1 answer
  • Find the least common denominator of the fractions 1/10 and 2/4
    8·1 answer
  • Is 5 a factor of the number 35 yes or no
    14·2 answers
  • Which of the following explains how to use partial quotients to find 832 ÷ 26 ?
    15·1 answer
  • The circumference of a circle can be found using the
    8·1 answer
  • С<br> 5 km<br> 12 km<br> What is the length of the hypotenuse?
    11·1 answer
  • What should be done to both sides of the equation in order to solve w - 9 = 15?
    15·2 answers
  • Please answer will mark brainliesttt
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!