All categories

4 years ago

What causes light to bend when it moves from one transparent medium to another?

Physics

2 answers:

Kay [80]4 years ago

4 0

Answer:

A change in speed

Explanation:

Light bends when it moves at a particular angle into a medium that has a different refractive index than the one it was coming from.

This bending is as a result of the change in speed of light as it enters the medium with a different refractive index.

This action is known as Refraction of light.

Refraction depends on the change in speed of light as it changes media and the angle of refraction depends on the angle of incidence of the ray of light and the refractive index of the material.

lapo4ka [179]4 years ago

3 0

Whenever light goes from transparent to another medium or from rarer to denser medium or vice versa, it's speed changes and hence light bends.

You might be interested in

Batman recharges his Bat-taser with 2.5mj of energy in 15 minutes. How much power does it draw from the mains?

BabaBlast [244]

That would be 0.16 per min

3 0

4 years ago

Evaluate how a reduction in the number of condensation nuclei in the tropo-

marta [7]

Answer:

i do not no sory

Explanation:

6 0

3 years ago

Can someone help meeeeee... show how to solve it plzzzzzzzz

liubo4ka [24]

<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

$F=G\frac{m_{1}m_{2}}{r^2}$

Where:

$F$ is the module of the force exerted between both bodies

$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

In this case we have a gravitation force $F_{1}=16units$ , given by the formula written at the beginning. Let’s rename the distance $r$ as $d$ :

$F_{1}=G\frac{m_{1}m_{2}}{d^2}$ (1)

And we are asked to find the gravitation force $F_{2}$ with a given distance of $\frac{d}{2}$ :

$F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}$

$F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}$ (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate $G m_{1}m_{2}$ in both equations: