The formula for the torque is

<span>τf = p F

where

</span><span>τf is the torque

p is the distance where the force is applied by the tendon

F is force applied by the tendon

If there are given values, substitute in the equation and solve for the torque.</span>

First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:

2as = v² - u²

Because the final velocity v is 0 in such cases

s = -u²/2a; because both u and a are downwards, the negative sign cancels

s = 14.5² / 2*9.81

s = 10.72 meters

Next, to find the time taken to reach the ground, we need the height above the ground. This is:

45 + 10.72 = 55.72 m

We will use the formula

s = ut + 0.5at²

to find the time taken with the initial velocity u = 0.

55.72 = 0.5 * 9.81 * t²

t = 3.37 seconds

**Answer:**

The hummingbird travels the total distance is 10 m

**Explanation:**

**Given that,**

A hummingbird flies forward and backward.

**According to figure,**

**We know that,**

The total distance is equal to the sum of all distance.

Forward direction is positive and backward direction is negative.

**We need to calculate the hummingbird travels the total distance**

**Using figure,**

Put the value into the formula

**Hence, The hummingbird travels the total distance is 10 m.**

**Answer:**

**Explanation:**

First, It's important to remember F = ma, and in this problem m = 13.3 kg

This can be reduced to a simple system of equations problem. Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them. So let's call them F1 and F2, with F1 arger than F2. Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.

Can you solve this system of equations seeing them like this, or do you need more help?

**Answer:**

1.01 × 10⁵ Pa

**Explanation:**

At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.

We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.

Pressure at a depth is given by :

Where

is the density of air,

So,

Total pressure, P = Atmospheric pressure + 12 Pa

= 1.013 × 10⁵ Pa + 12 Pa

= 1.01 × 10⁵ Pa

Hence, the total pressure is 1.01 × 10⁵ Pa.