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vova2212 [387]
3 years ago
13

Why do the magnetic forces acting on the coil change as the current running through the coil changes?

Physics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer: The changing magnetic field caused by the material's motion induces a current in the coil of wire proportional to the change in field. If a 0 is represented, the magnetic field does not change between the two domains of a bit, so no current is induced as the magnetic material passes the coil.

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I NEED HELP PLEASE, THANKS :) What does it mean when white light is diffracted and at a particular location the color seen is bl
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Answer:

This is because white light consists of 7 colours with different angles o deviation or retraction.

Explanation:

When a narrow beam of light is refracted by a prism the light spreads into a band of colours (called the spectrum of light )

But in this case if a blue colour is observed it is due to the angle of refraction ,for instance red is refracted the least and hence is seen

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Humans sleep in cycles, usually two or three cycles per night. There is a point in each cycle when waking up will leave the slee
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A blank is any disturbance that carries energy from one place to another through matter and space.
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<h3>Answer;</h3>

<em>A wave </em>

<em><u>A wave</u></em> is any form of a disturbance that carries energy from one place to another through a matter and space

<h3>Explanation;</h3>
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  • Electromagnetic waves are those waves whose transmissions occurs through the space, they do not require material medium for transmission,for example, radio waves, while mechanical waves are those that require material medium for transmission, for example sound waves.
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A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci
larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

#SPJ1

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In an experiment to determine the s.h.c. of lead, a 0.80 kg block of lead is heated using a
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