F(x) = x2 + 1 f(f(x))
2 answers:
<h3>Answer: f( f(x) ) = x^4 + 2x^2 + 2</h3>
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Work Shown:
f(x) = x^2 + 1
f(x) = ( x )^2 + 1
f( f(x) ) = ( f(x) )^2 + 1 .. replace every x with f(x)
f( f(x) ) = ( x^2+1 )^2 + 1 .. plug in f(x) = x^2+1
f( f(x) ) = ( x^2+1 )( x^2+1 )+1
f( f(x) ) = y( x^2+1 )+1 .... let y = f(x) = x^2+1
f( f(x) ) = y*x^2+y+1 ... distribute
f( f(x) ) = x^2*( y ) + ( y ) + 1
f( f(x) ) = x^2*( x^2+1 ) + (x^2+1) + 1 .... plug in y = x^2+1
f( f(x) ) = x^4 + x^2 + x^2 + 1 + 1
f( f(x) ) = x^4 + 2x^2 + 2
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Side note: , the small circle indicates function composition. It's similar to
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Answer:
x equals five thirteenths
Step-by-step explanation:
To solve this, we will follow the steps below;
× x +
= 4 × x
+
= 4x
= 4x
Multiply both-side of the equation by 4
× 4= 4x × 4
On the left-hand side of the equation 4 will cancel-out 4, thus the equation becomes;
3x + 5 = 16x
subtract 3x from both-side of the equation
16x - 3x = 5
13x = 5
Divide both-side of the equation by 13
=
(On the left-hand side of the equation 13 at the numerator will cancel-out 13 at the denominator while on the right-hand side of the equation 5 will be divided by 13)
x =
x equals five thirteenths