Answer:
2.10 s, 10.40 s.
Step-by-step explanation:
We know that the height of the rocket is given by the function:

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

The last is a quadratic equation, which can be put in the form
and solved applying the formula:

So, let's put the equation on the form
adding
and subtracting
to each side of the equation; the result is:

So, we note that a=16, b=-200, and c=350.
Then,


According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.
1) 0.78
2) 34.28
This is because the number in the 3rd decimal place for both numbers is 5 or above so it is rounded up rather than down.
Answer:
I tried everything and either I'm doing it wrong or you wrote this wrong
Step-by-step explanation:
Answer:
is congruent because are parralel