Answer:
sorry you can send me picture of work
Step-by-step explanation:
ok send me and get answers
Answer:
<em>5</em><em> players participated in the tournament.</em>
Step-by-step explanation:
In a small chess tournament, 20 matches were played.
Let us assume that n number of players participated in the tournament
As in each game 2 players play, so the number of ways they can play is,
![=\ ^nC_2](https://tex.z-dn.net/?f=%3D%5C%20%5EnC_2)
As they played 2 games with every other participant in the tournament.
So the total number of games is,
![=\ 2\times ^nC_2](https://tex.z-dn.net/?f=%3D%5C%202%5Ctimes%20%5EnC_2)
But it is given to be 20, so
![\Rightarrow \ 2\times ^nC_2=20](https://tex.z-dn.net/?f=%5CRightarrow%20%5C%202%5Ctimes%20%5EnC_2%3D20)
![\Rightarrow \ ^nC_2=10](https://tex.z-dn.net/?f=%5CRightarrow%20%5C%20%5EnC_2%3D10)
![\Rightarrow \dfrac{n!}{2!(n-2)!}=10](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7Bn%21%7D%7B2%21%28n-2%29%21%7D%3D10)
![\Rightarrow \dfrac{n(n-1)}{2}=10](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7Bn%28n-1%29%7D%7B2%7D%3D10)
![\Rightarrow {n(n-1)=20](https://tex.z-dn.net/?f=%5CRightarrow%20%7Bn%28n-1%29%3D20)
As
, so we get n=5.
Therefore, 5 players participated in the tournament.
The complete question in the attached figure
we know that
[arcs rc +arc cs arc sm]---------------> they take up half a circle-------->180°
<span> they are all congruent
so
divide 180 by 3 ----------------> 180/3=60</span>°
Find the length of arc rc=60°<span>
if 360</span>°----------------> (2*pi*7) length of circumference
60° -------------------> X
<span>X=60*2*pi*7/360------------> 7.327 units
the answer is
</span>
the length of arc rc= <span>
7.33 units</span>
3/8 = 0.375
40/0.375 = 106 and 2/3
Answer: -80
Step-by-step explanation: