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3 years ago

13

Convert the radian measure to degree measure. Use the value of π found on a calculator, and round answers to two decimal places.

(5 points)
negative pi divided by three

negative pi divided by three degrees

-1.05°

-60π°

-60°

1 answer:

Leni [432]3 years ago

3 0

The answer is -60 degrees

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If anyone could please help me with this question???I know that you can get three triangles out of the shape.

dem82 [27]

Answer:

See below.

Step-by-step explanation:

The triangles are similar because the angles marked 125 are equal and the sides either side of these angle are in the same ratio:

1.3 / 2.5 = 2.6 /5.

If we are given the length of AE we would find CF from the equation:

1.3 / 2.5 = CF / AE

CF = (1.3 * AE) / 2.5.

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3 years ago

What integer is equivalent to 25 3/2

antiseptic1488 [7]

<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
</span></span>

3 0

3 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

Pls help (links will get reported)

joja [24]

Answer:

-938 ft

Step-by-step explanation:

the bird will be going down in elevation. the distance between -422 and -1360

-1360+422= -938

3 0

3 years ago

I need help with 1 and 3 please

schepotkina [342]

For #1
city A's mean would be 10.5, then you would divide it by the number of numbers there is which is 5,So 10.5/5 is 2.1

city B's mean would be 11.6 then you would divide it by the number of numbers there is which is 5, So 11.6/5 is 2.32.

thats all I have don't know how to do #3 sorry

4 0

3 years ago