Answer:
21n² - 28n + 7
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
3n(7n - 7) - 1(7n - 7) ← distribute both parenthesis
= 21n² - 21n - 7n + 7 ← collect like terms
= 21n² - 28n + 7
Answer:
$160
Step-by-step explanation:
80 * $2
$160
Answer: $160
Answer:
x=-2
Step-by-step explanation:
-2x=4
Divide each side by -2
-2x/-2=4/-2
x = -2
Take 9 time 30 then 9 time 6. Next add them both together.
(9x30)+(9x6)
270+54
324
Given:
The graph of a line segment.
The line segment AB translated by the following rule:
![(x,y)\to (x+4,y-3)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28x%2B4%2Cy-3%29)
To find:
The coordinates of the end points of the line segment A'B'.
Solution:
From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).
We have,
![(x,y)\to (x+4,y-3)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28x%2B4%2Cy-3%29)
Using this rule, we get
![A(-2,-3)\to A'(-2+4,-3-3)](https://tex.z-dn.net/?f=A%28-2%2C-3%29%5Cto%20A%27%28-2%2B4%2C-3-3%29)
![A(-2,-3)\to A'(2,-6)](https://tex.z-dn.net/?f=A%28-2%2C-3%29%5Cto%20A%27%282%2C-6%29)
Similarly,
![B(4,-1)\to B'(4+4,-1-3)](https://tex.z-dn.net/?f=B%284%2C-1%29%5Cto%20B%27%284%2B4%2C-1-3%29)
![B(4,-1)\to B'(8,-4)](https://tex.z-dn.net/?f=B%284%2C-1%29%5Cto%20B%27%288%2C-4%29)
Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).