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Phantasy [73]
3 years ago
8

Verify that whether -2 and 3 are zeroes of the polynomial x^2-x=6PLEASE HELP​

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

Both give remainder 0 for the polynomial

Step-by-step explanation:

p(-2) = (-2)² - (-2) - 6

= 6 - 6 = 0

p(3) = (3)² - 3 - 6

= 9 - 9 = 0

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One positive number is three more than twice another. If their product is 629, find the numbers.
sineoko [7]

Answer:

x = 17 and y = 37

Step-by-step explanation:

Let the numbers be x and y.

y = 3 + 2x

xy = 629

substituting y in the second equation we get

x(3+2x) = 629

3x + 2x^{2} = 629

2x^{2} + 3x - 629 = 0

Solving a quadratic equation by using its formula:

x = [-3 ±√(9-4(2)(-629)] / 4

x = [-3 ± √5041] / 4

x = [-3 ± 71] / 4

x = 17 and \frac{-37}{2}

Ignore the negative number in x and just use x = 17 in the first equation we get

y = 3 + 2(17) = 37

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3 years ago
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answer
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Step-by-step explanation:

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Jorge lives closer to the playground than Lynne.
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