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polet [3.4K]
3 years ago
5

What is the surface area of the cone? (radius 10in height 26in)

Mathematics
1 answer:
MArishka [77]3 years ago
8 0

Answer:

C) 360pi in2

Step-by-step explanation:

Given:

radius, r= 10in

height, h=26in

surface area of the cone, T.S.A= ?

T.S.A=πrl +πr^2

         =π(10)(26) +π(10)^2

         =260π+100π

         =360π^2 !

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Find the median, Q1, Q3, interquartile range (IQR), and list any outliers. 2) 74, 63, 69, 62, 33, 79, 70, 60, 107, 119
e-lub [12.9K]

Answer:

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

Q_1 =62

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

Q_3 =79

And finally the median can be calculated with the average of the two moddlie values and we got:

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And the IQr would be:

IQR = 79-62= 17

Step-by-step explanation:

Assuming that 2 is not part of the data we have:

74, 63, 69, 62, 33, 79, 70, 60, 107, 119

We can sort the values on increasing order and we got:

33  60  62  63  69  70  74  79 107 119

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33  60  62  63  69

Q_1 =62

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70  74  79 107 119

Q_3 =79

And finally the median can be calculated with the average of the two moddlie values and we got:

Median= \frac{69+70}{2} =69.5

And the IQr would be:

IQR = 79-62= 17

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Step-by-step explanation:

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Step-by-step explanation:

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