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Vikki [24]
4 years ago
6

Factor the trigonometric equation. cos2x-cosx

Mathematics
1 answer:
prisoha [69]4 years ago
4 0

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

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In 25 words or fewer, is this solution reasonable? Why or why not?
Julli [10]

Step-by-step explanation:

This solution is reasonable because equal slopes are parallel and negative reciprocals are perpendicular. Four right angles make up a rectangle, and this fulfills it

7 0
3 years ago
The bus is scheduled to leave at 16:24pm. It doesn't actually leave until 7 minutes later. You
aev [14]

Answer:

46 minutes

Step-by-step explanation:

4 0
3 years ago
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in a school election 1/3 of the students vote. there are 655 ballots. find the number of students at the school
Basile [38]

Answer:

45

Step-by-step explanation:

2*23

6 0
3 years ago
I need help on questions 48 49 and 50 and u need to find the surface area of the 3 polyhedras please and thank you!
White raven [17]

48. The surface area of a cylinder is given by

... A = 2πr² + 2πrh = 2πr(r+h)

For r = 13 mi and h = 7 mi, this becomes

... A = 2π(13 mi)(13 mi + 7 mi) = 520π mi²

The surface area of the cylinder is 520π mi² ≈ 1634 mi².

49. The surface area of a rectangular prism is

... A = 2(LW + H(L+W))

For L = 20 m, W = 10 m, H = 7 m, this becomes

... A = 2((20 m)(10 m) + (7 m)(20 m + 10 m)) = 2(200 m² + 210 m²) = 820 m²

The surface area of the prism is 820 m².

50. The formula is the same as for problem 48.

For r = 10 m and h = 13 m, this becomes

... A = 2π(10 m)(10 m + 13 m) = 460π m² ≈ 1445 m²

The surface area of the cylinder is 460π m² ≈ 1445 m².

_____

When calculations are repetitive, it is convenient to let a calculator or spreadsheet do them.

7 0
4 years ago
-2x + y =0 <br> 5x + 3y = -11
Ivahew [28]

Answer:

(-1, -2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing

Step-by-step explanation:

<u>Step 1: Define Systems</u>

-2x + y = 0

5x + 3y = -11

<u>Step 2: Rewrite Systems</u>

-2x + y = 0

  1. Add 2x on both sides:                    y = 2x

<u>Step 3: Redefine Systems</u>

y = 2x

5x + 3y = -11

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                         5x + 3(2x) = -11
  2. Multiply:                                    5x + 6x = -11
  3. Combine like terms:                11x = -11
  4. Isolate <em>x</em>:                                   x = -1

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    y = 2x
  2. Substitute in <em>x</em>:                       y = 2(-1)
  3. Multiply:                                  y = -2

<u>Step 6: Graph Systems</u>

<em>Check the solution set.</em>

3 0
3 years ago
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