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Vikki [24]
4 years ago
6

Factor the trigonometric equation. cos2x-cosx

Mathematics
1 answer:
prisoha [69]4 years ago
4 0

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

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7 0
3 years ago
The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters
Vera_Pavlovna [14]

Answer:

The approximate length of the actual car is <u>43 feet</u>.

Step-by-step explanation:

Given:

The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters.

Now, to find the approximate length of the actual car.

Let the actual length of the car is x.

The length of a model car in the set is 150 millimeters.

As, given the scale on a model railroad train set is 3.5 millimeters to 1 foot.

<em>So, 3.5 millimeters equivalent to 1 foot.</em>

<em>Thus, 150 millimeters to </em>x<em>.</em>

Now, to get the actual length of the car by using cross multiplication method:

\frac{3.5}{1} =\frac{150}{x}

<em>By using cross multiplying we get:</em>

3.5x=150

<em>Dividing both sides by 3.5 we get:</em>

x=42.85\ feet.

<em><u>The approximate length of the actual car = 43 feet.</u></em>

Therefore, the approximate length of the actual car is 43 feet.

3 0
3 years ago
Read 2 more answers
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