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4 years ago

Factor the trigonometric equation. cos2x-cosx

Mathematics

1 answer:

prisoha [69]4 years ago

4 0

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

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Solve the compound inequality, showing your work. Name the solution set and then draw the graph of the solution set.y-2<-5 or

Ede4ka [16]

$y - 2 \ \textless \ -5$
$y \ \textless \ -5 + 2$
$y \ \textless \ -3$

and

$y - 2 \ \textgreater \ 5$
$y \ \textgreater \ 5 + 2$
$y \ \textgreater \ 7$

The value of y is greater than 7 and less than -3
The number line is shown below

8 0

4 years ago

Solve log2(x + 5) + log2(x − 5) = log211.

UkoKoshka [18]

Answer:

x = 6

Step-by-step explanation:

log2(x + 5) + log2(x − 5) = log2 11.

We know that loga (b) + log a(c) = log a( bc)

log2(x + 5) (x − 5) = log2(11)

Multiply

log2(x^2 -25) = log2(11)

Raise each side to the power of 2

2^log2(x^2 -25) = 2^log2(11)

x^2 - 25 = 11

Add 25

x^2 -25 +25 = 25+11

x^2 = 36

Taking the square root of each side

x = ±6

But x cannot be negative because then the log would be negative in log2(x-5) and that is not allowed

x = 6

6 0

3 years ago

Read 2 more answers

Explain why it works to break apart a number by place values to multiply

kramer

Well first of all if I had a multiplication question such as 12,000×1000 of course you would know it would be 12,000 well you would always use your place value chart saying ones tens hundreds thousands and thousands and hundreds

6 0

3 years ago

Read 2 more answers

Someone please help me. SERIOUS answers only!!!!

IRINA_888 [86]

Hey there!

The answer should be 30%

4 0

4 years ago

How would I solve for x and y?

Strike441 [17]

x =65/2 = 32.5

y = 180 - 2(65)
y = 180 - 130
y = 50

hope it helps

7 0

3 years ago