Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.
Step-by-step explanation:
I suppose that the "legs" of a triangle rectangle are the cathati.
if L is the length of the shorter leg, 2*L is the length of the longest leg.
Now you can remember the relation:
Tan(a) = (opposite cathetus)/(adjacent cathetus)
Then there is one acute angle calculated as:
Tan(θ) = (shorter leg)/(longer leg)
Tan(φ) = (longer leg)/(shorter leg)
And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.
Then we need to find θ and φ.
Tan(θ) = L/(2*L)
Tan(θ) = 1/2
θ = Atan(1/2) = 26.57°
Tan(φ) = (2*L)/L
Tan(φ) = 2
φ = Atan(2) = 63.43°
Then the ratio between the larger acute angle and the smaller acute angle is:
R = (63.43°)/(26.57°) = 2.39
This means that the larger acute angle is 2.39 times the smaller acute angle.
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Answer:
Step-by-step explanation:
You know the linear pair z° and 105° are supplementary angles, so ...
z = 180 -105 = 75
The other base angle of the isosceles triangle has the same measure, 75°. __
Then x can be found either from the sum of interior angles of the triangle, or from the relation of 105° to the "remote interior angles". The first relation gives ...
75° +75° +x° = 180° ⇒ x = 180 -150 = 30
The second relation gives ...
75° +x° = 105° ⇒ x = 105 -75 = 30
__
y° is supplementary to the left-side base angle, so is ...
y = 180 -75 = 105
Of course, you could also figure y from the symmetry of the figure.
The values of x, y, z are 30, 105, 75, respectively.
Answer:
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Step-by-step explanation:
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